An ionic bond is formed between a cation A1 and an anion B2. How would the energy of the ionic bond [see Equation (9.2)] be affe
1 answer:
Answer:
Before we start answering, the appropiate equation for the energy of an ionic bond should be written:
Where A1+, B2- are the charges of the ions and Ro is the interionic distance (the sum of the radii of the anion and cation). C is a constant depending on the ionic structure.
Explanation:
Examining the equation above, we have the following scenarios:
a) Doubling the radius of A1 would mean a decrease on the energy of the ionic bond.
b) Tripling the charge of A1 would also triple the energy of the ionic bond
c)Doubling the charges on A1 and B2 would quadruple the energy of the ionic bond.
d)Decreasing the radii of A1 and B2 to half their original values would double the energy of the energy bond.
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Answer:
D It must be equal to 1.00
Explanation:
The refraction in the second medium must be equal to 1. The refraction index is given as the ration of the angle of incidence to the angle of refraction. This is given as a fraction. In other words:
where Θ₁ and Θ₂ are angles of incidence an refraction, and n is the refractive index.
At a critical angle, the refraction is equal to the reflection inside the medium. This results in a phenomenon called total internal reflection where light is reflected internally in the medium.