Answer:
(CH2)3CH3 > CH2CH2CH3 > CH2CH3 > CH3
Explanation:
Giving the following ; CH3, CH2CH3, CH2CH2CH3, (CH2)3CH3
Priority increases as the number of CH2 group increases and vice versa, as such the one with more CH2 group will be the highest priority and the least compound with the small CH2 group attached, will have the smallest priority.
The arrangement is as follows ; (CH2)3CH3 > CH2CH2CH3 > CH2CH3 > CH3
Answer: because ch4 is not considered a acid they said it is too weak
Explanation:
Answer:
the answer is C
Explanation:
This is because group6 elements are diatomic and when they are chemically combined their subscript 2 cancels out
One candela per steradian is termed a lumen, which is the measure of light intensity people are most familiar with One foot candle is equivalent to one lumen per square foot
Answer:
1) Maximun ammount of nitrogen gas: ![m_{N2}=10.682 g N_2](https://tex.z-dn.net/?f=m_%7BN2%7D%3D10.682%20g%20N_2)
2) Limiting reagent: ![NO](https://tex.z-dn.net/?f=NO)
3) Ammount of excess reagent: ![m_{N2}=4.274 g](https://tex.z-dn.net/?f=m_%7BN2%7D%3D4.274%20g)
Explanation:
<u>The reaction </u>
![2 NO (g) + 2 H_2 (g) \longrightarrow N_2 (g) + 2 H_2O (g)](https://tex.z-dn.net/?f=2%20NO%20%28g%29%20%2B%202%20H_2%20%28g%29%20%5Clongrightarrow%20N_2%20%28g%29%20%2B%202%20H_2O%20%28g%29)
Moles of nitrogen monoxide
Molecular weight: ![M_{NO}=30 g/mol](https://tex.z-dn.net/?f=M_%7BNO%7D%3D30%20g%2Fmol)
![n_{NO}=\frac{m_{NO}}{M_{NO}}](https://tex.z-dn.net/?f=n_%7BNO%7D%3D%5Cfrac%7Bm_%7BNO%7D%7D%7BM_%7BNO%7D%7D)
![n_{NO}=\frac{22.9 g}{30 g/mol}=0.763 mol](https://tex.z-dn.net/?f=n_%7BNO%7D%3D%5Cfrac%7B22.9%20g%7D%7B30%20g%2Fmol%7D%3D0.763%20mol)
Moles of hydrogen
Molecular weight: ![M_{H2}=2 g/mol](https://tex.z-dn.net/?f=M_%7BH2%7D%3D2%20g%2Fmol)
![n_{H2}=\frac{m_{H2}}{M_{H2}}](https://tex.z-dn.net/?f=n_%7BH2%7D%3D%5Cfrac%7Bm_%7BH2%7D%7D%7BM_%7BH2%7D%7D)
![n_{H2}=\frac{.5.8 g}{2 g/mol}=2.9 mol](https://tex.z-dn.net/?f=n_%7BH2%7D%3D%5Cfrac%7B.5.8%20g%7D%7B2%20g%2Fmol%7D%3D2.9%20mol)
Mol rate of H2 and NO is 1:1 => hydrogen gas is in excess
1) <u>Maximun ammount of nitrogen gas</u> => when all NO reacted
![m_{N2}=0.763 mol NO* \frac{1 mol N_2}{2 mol NO}*\frac{28 g N_2}{mol N_2}](https://tex.z-dn.net/?f=m_%7BN2%7D%3D0.763%20mol%20NO%2A%20%5Cfrac%7B1%20mol%20N_2%7D%7B2%20mol%20NO%7D%2A%5Cfrac%7B28%20g%20N_2%7D%7Bmol%20N_2%7D)
![m_{N2}=10.682 g N_2](https://tex.z-dn.net/?f=m_%7BN2%7D%3D10.682%20g%20N_2)
2) <u>Limiting reagent</u>:
3) <u>Ammount of excess reagent</u>:
![m_{N2}=(2.9 mol - 0.763 mol NO* \frac{1 mol H_2}{1 mol NO})*\frac{2 g H_2}{mol H_2}](https://tex.z-dn.net/?f=m_%7BN2%7D%3D%282.9%20mol%20-%200.763%20mol%20NO%2A%20%5Cfrac%7B1%20mol%20H_2%7D%7B1%20mol%20NO%7D%29%2A%5Cfrac%7B2%20g%20H_2%7D%7Bmol%20H_2%7D)
![m_{N2}=4.274 g](https://tex.z-dn.net/?f=m_%7BN2%7D%3D4.274%20g)