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tensa zangetsu [6.8K]
3 years ago
8

PLEASE ANSWER ASAP

Chemistry
2 answers:
Vsevolod [243]3 years ago
7 0

Answer:

The charge of the purple circles should be positive because they represent the nuclei.

Explanation:

AnnZ [28]3 years ago
7 0

Answer:

The correct feedback Zoe will have from this diagrammatic report will be the option B, which is the charge of the purple circles, should be positive because they represent the nuclei.

Explanation:

Metals have fewer electrons in their outermost electron shells, which make them be good electron givers or better reducing agent, also due to their low ionization energy. Therefore, metals tend to become positively charged nucei after losing electrons to the neighboring atoms.

In the case of the metallic bond, the neighboring atoms are still metals. The big purple circles which represent the bigger metallic atoms should be marked with a positive sign, while the small circles in between the bid circles should be marked with negative signs.

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How many mL of a 1.48 M calcium hydroxide solution are needed to neutralize 36.0 mL of a 1.63 M hydrochloric acid solution
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The volume (in mL) of calcium hydroxide, Ca(OH)₂ needed for the reaction is 19.8 mL

<h3>Balanced equation </h3>

2HCl + Ca(OH)₂ —> CaCl₂ + 2H₂O

From the balanced equation above,

  • The mole ratio of the acid, HCl (nA) = 2
  • The mole ratio of the base, Ca(OH)₂ (nB) = 1

<h3>How to determine the volume of Ca(OH)₂ </h3>
  • Molarity of base, Ca(OH)₂ (Mb) = 1.48 M
  • Volume of acid, HCl (Va) = 36 mL
  • Molarity of acid, HCl (Ma) = 1.63 M
  • Volume of base, Ca(OH)₂ (Vb) =?

MaVa / MbVb = nA / nB

(1.63 × 36) / (1.48 × Vb) = 2

58.68 / (1.48 × Vb) = 2

Cross multiply

2 × 1.48 × Vb = 58.68

2.96 × Vb = 58.68

Divide both side by 2.96

Vb = 58.68 / 2.96

Vb = 19.8 mL

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1. During diffusion, when the concentration of molecules on both sides of a membrane is the same, the molecules will continue to move across the membrane in both directions.

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Answer: observe the rate of the reaction and then observe it again with the catalyst included.

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