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3 years ago

PLEASE ANSWER ASAP

Chemistry

2 answers:

Vsevolod [243]3 years ago

7 0

Answer:

The charge of the purple circles should be positive because they represent the nuclei.

Explanation:

AnnZ [28]3 years ago

7 0

Answer:

The correct feedback Zoe will have from this diagrammatic report will be the option B, which is the charge of the purple circles, should be positive because they represent the nuclei.

Explanation:

Metals have fewer electrons in their outermost electron shells, which make them be good electron givers or better reducing agent, also due to their low ionization energy. Therefore, metals tend to become positively charged nucei after losing electrons to the neighboring atoms.

In the case of the metallic bond, the neighboring atoms are still metals. The big purple circles which represent the bigger metallic atoms should be marked with a positive sign, while the small circles in between the bid circles should be marked with negative signs.

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Answer:

$\large \boxed{109.17 \, ^{\circ}\text{C}}$

Explanation:

Data:

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V = 4.70 gal

ρ(EG) = 1.11 g/mL

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The formula for the boiling point elevation ΔTb is

$\Delta T_{b} = iK_{b}b$

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2. Kilograms of water

$m = 0.50 \times \text{4.70 gal} \times \dfrac{\text{3.785 L}}{\text{1 gal}} \times \dfrac{\text{998 g}}{\text{1 L}} \times \dfrac{\text{1 kg}}{\text{1000 g}} = \text{8.88 kg}$

3. Molal concentration of EG

$b = \dfrac{\text{159 mol}}{\text{8.88 kg}} = \text{17.9 mol/kg}$

4. Increase in boiling point

$\rm \Delta T_{b} = iK_{b}b = 1 \times 0.512 \, \, ^{\circ}\text{C} \cdot kg \cdot mol^{-1} \, \times 17.9 \cdot mol \cdot kg^{-1} = 9.17 \, ^{\circ}\text{C}$

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$\rm T_{b} = T_{b}^{\circ} + \Delta T_{b} = 100.00 \, ^{\circ}\text{C} + 9.17 \, ^{\circ}\text{C} = \mathbf{109.17 \, ^{\circ}C}\\\rm \text{The boiling point of the solution is $\large \boxed{\mathbf{109.17 \, ^{\circ}C}}$}$

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