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Softa [21]
4 years ago
5

Sodium metal (Na) and chlorine gas (Cl) are two reactive and dangerous elements. Chlorine is a halogen gas that can cause respir

atory damage and sodium is an alkali metal that reacts violently with water. What happens to the properties of sodium and chlorine when they react to form sodium chloride (NaCl), common table salt? A) The properties of both sodium and chlorine change. B) The properties of both sodium and chlorine remain the same. C) The properties of sodium are different but chlorine remains a dangerous gas. D) The properties of sodium remain the same but the properties of chlorine change.
Chemistry
1 answer:
Aleonysh [2.5K]4 years ago
6 0
They<span> combine as atoms, and separate as ions. When </span>sodium and chlorine<span> atoms come together to </span>form sodium chloride(NaCl<span>), </span>they<span> transfer an electron. The </span>sodium<span> (Na) atom transfers one electron to the </span>chlorine<span> (Cl) atom, so that </span>they<span>both have full outer shells. ... When this </span>happens<span>, the atom is called a positive ion.

What do think the answer is now?</span>
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What is the value for the reaction: N2(g) + 2 O2(g) --&gt; N2O4(g) in terms of K values from the reactions:
Valentin [98]

Answer : The correct expression will be:

K=(K_1)^2\times K_2

Explanation :

The chemical reactions are :

(1) \frac{1}{2}N_2(g)+\frac{1}{2}O_2(g)\rightleftharpoons NO(g) K_1

(2) 2NO(g)+O_2(g)\rightleftharpoons N_2O_4(g) K_2

The final chemical reaction is :

N_2(g)+2O_2(g)\rightleftharpoons N_2O_4 K=?

Now we have to calculate the value of K for the final reaction.

Now equation 1 is multiply by 2 and then add both the reaction we get the value of 'K'.

If the equation is multiplied by a factor of '2', the equilibrium constant will be the square of the equilibrium constant of initial reaction.

If the two equations are added then equilibrium constant will be multiplied.

Thus, the value of 'K' will be:

K=(K_1)^2\times K_2

6 0
3 years ago
Are elecronegativity values higher for metals than nonmetals.
Leya [2.2K]

Non-metals, which are organized on the right side of the periodic table, have higher electronegativity values than the metals.

Hope this helped!

3 0
3 years ago
Calculate the [H3O+] of solutions a and b; calculate the [OH-] solutions c and d.
patriot [66]

Answer:

I got the answers but it won't let me post it correctly on here....

Explanation:

9.) 10-2.76 =0.0174 [H30+]= 1.74*10-3 M

10.)10-3.65=0.00224  [H3O+] =2.24*10-2 M

11.)10-3.65=0.00224 [OH-]= 2.224*10-4M

12.)10-6.87=0.00000135  [OH-]= 1.35*10-7M

3 0
3 years ago
A piece of copper has a mass of 660 g. How many atoms does the sample contain?
son4ous [18]
The conversions that will be used are:

1 mole of copper / 63.5 grams of copper
6.02 x 10²³ atoms of copper / 1 mole of copper

Multiplying the given mass by these conversions,

660 g * (1 mol Cu / 63.5 g Cu) * (6.02 x 10²³ Cu atoms / 1 mole Cu)

The sample contains 6.25 x 10²⁴ atoms of copper
4 0
3 years ago
The combination of potassium-sparing diuretics and salt substitutes can result in dangerously high blood levels of:
alisha [4.7K]

Answer:

b. potassium.  

Explanation:

Potassium-sparing diuretics and salt substitutes are diuretics that eliminate salt and water but save potassium. They act by inhibiting the conducting sodium channels in the collecting tubule, such as amiloride and triamterene, or by blocking aldosterone, such as spironolactone.

Concomitant use of potassium-sparing diuretics together with salt substitutes may result in dangerously high blood levels of serum potassium. For this reason, it is important to consult a physician before taking these substances at the same time to avoid potential problems with potassium accumulation.

4 0
3 years ago
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