50π m ≈ 157 m
Explanation:
100 rev/min (2π rad/rev) / (60 sec/min) = 3⅓π rad/s
d = ωrt = 3⅓π(0.50)(30) = 50π m ≈ 157 m
For a concave mirror, the radius of curvature is twice the focal length of the mirror:

where f, for a concave mirror, is taken to be positive.
Re-arranging the formula we get:

and since the radius of curvature of the mirror in the problem is 24 cm, the focal length is
Answer: The acceleration will be greater in the kickball than the soccer ball since the kick ball has a smaller mass and provided they are acted upon with equal force magnitude.
Explanation:
We can prove this by substituting with numerical values.
Say the force she kicked both balls with was 30 N. The mass of the soccer ball is 10kg and the mass of the kickball is 6kg.
Applying Newtons Second Law, F = ma
For the soccer ball:
30 = 10a
a = 30/10
a = 3
For the kickball:
30 = 6a
a = 30/6
a = 5
Hence the kickball will travel with a greater acceleration given the same force is acted upon and has a smaller mass than the soccer ball
Hope this helps, brainliest would be appreciated :)
3.85 pounds is the answer
Density and boilind point