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3 years ago

10

Draw the major byproduct of the reaction (not the minor species discussed in q2b). At which stage did you remove it from your sa

mple?

1 answer:

givi [52]3 years ago

3 0

You need to do something like that your self so sorry can help.

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Mama L [17]

<u>Answer:</u> The number of gold atoms per cubic centimeters in the given alloy is $1.83\times 10^{22}$

<u>Explanation:</u>

To calculate the number of gold atoms per cubic centimeters for te given silver-gold alloy, we use the equation:

$N_{Au}=\frac{N_AC_{Au}}{(\frac{C_{Au}M_{Au}}{\rho_{Au}})+(\frac{M_{Au}(100-C_{Au})}{\rho_{Ag}})}$

where,

$N_{Au}$ = number of gold atoms per cubic centimeters

$N_A$ = Avogadro's number = $6.022\times 10^{23}atoms/mol$

$C_{Au}$ = Mass percent of gold in the alloy = 42 %

$\rho_{Au}$ = Density of pure gold = $19.32g/cm^3$

$\rho_{Ag}$ = Density of pure silver = $10.49g/cm^3$

$M_{Au$ = molar mass of gold = 196.97 g/mol

Putting values in above equation, we get:

$N_{Au}=\frac{(6.022\times 10^{23}atoms/mol)\times 48\%}{(\frac{48\%\times 196.97g/mol}{19.32g/cm^3})+(\frac{196.97g/mol\times 58\%}{10.49g/cm^3})}\\\\N_{Au}=1.83\times 10^{22}atoms/cm^3$

Hence, the number of gold atoms per cubic centimeters in the given alloy is $1.83\times 10^{22}$

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This pair of molecules are _____.The figure shows two ball-and-stick models of molecules. The first consists of five black balls

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Alkanes

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The description of the first molecule corresponds to a cycloalkane. In the cycloalkanes for each carbon atom there are 2 hydrogen atoms (CnH2n = C5H10).

The second molecule corresponds to an open chain alkane, where for every carbon atom there is double plus 2 hydrogen atoms (CnH (2n + 2) = C5H12)

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