Answer
:
2. Hydrogen forms bonds through the overlap of 1s atomic orbitals and the sharing of electrons between atoms. Carbon forms bonds through the overlapping of sp hybrid atomic orbitals and the sharing of electrons between carbon atoms.
Explanation:
The H-H bond is formed by the overlap of two 1s orbitals and the sharing of electrons between the two atoms.
A carbon atom must use the overlap of hybridized atomic orbitals and the sharing of electrons to bond with another carbon atoms.
1. is <em>wrong</em> because H can use only its <em>1s orbital</em> for bonding.
3. is <em>wrong</em> because C must <em>share electrons</em> to form a carbon-carbon bond.
4. is <em>wrong</em> because <em>C does NOT use overlapping of 2s orbitals</em> for bonding. It uses the overlap of hybridized orbitals.
5. is <em>wrong</em> because H must <em>share electrons</em> to form an H-H bond.
State functions include density, internal energy, enthalpy, entropy. Such a relation cannot be written for path functions, especially since these cannot be defined for the limiting states. Path functions depend on the route taken between two states. Two examples of path functions are heat and work.
Answer:
To prepare 20,0 mL of the liquid mixture you should mix 15,3 mL of CHCl₃ with 4,7 mL of CHBr₃
Explanation:
Here you have two variables: The volume of both CHCl₃ (X) and CHBr₃ (Y). To find these two variables you must have, at least, two equations.
You know total volume is 20,0 mL. Thus:
X + Y = 20,0 mL (1)
The other equation is:
× 1,492 g/mL + 
× 2,890 g/mL = 1,82 g/mL (2)
If you replace (1) in (2):
× 1,492 g/mL + 
× 2,890 g/mL = 1,82 g/mL
Solving:
X = 15,3 mL
Thus, using (1):
20,0 mL - 15,3 mL = Y = 4,7 mL
Thus, to prepare 20,0 mL of the liquid mixture you must mix 15,3 mL of CHCl₃ with 4,7 mL of CHBr₃.
I hope it helps!
