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2 years ago

If you had 14.5 moles of gold, how many atoms would you expect to have?

Chemistry

1 answer:

Tju [1.3M]2 years ago

6 0

Answer:

(14.5 mol) x (6.022 x 10^23 atoms/mol) = 8.73 × 10^24 atoms

Explanation:

pls mark brainliest

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What is the percent by mass of oxygen in ca(oh)2? [formula mass = 74.1]

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16(2)/74.1=.431

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At 1000 K, Kp=19.9 for the reaction Fe2O3(s)+3CO(g)<--->2Fe(s)+3CO2(g) What are the equilibrium partial pressures of CO an

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Answer: The equilibrium concentration of CO is 0.243 atm

Explanation:

We are given:

Initial partial pressure of carbon dioxide = 0.902 atm

As, carbon dioxide is present initially. This means that the reaction is proceeding backwards.

For the given chemical equation:

$Fe_2O_3(s)+3CO(g)\rightleftharpoons 2Fe(s)+3CO_2(g)$

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$K_p=19.9$

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$19.9=\frac{(0.902-3x)^3}{(3x)^3}\\\\x=0.0810$

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3 years ago

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Which statement describes the moment magnitude scale?

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2 years ago

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H2 + NO → H2O + N2 If 180.5 grams of N2 are produced, how many grams of H2 were reacted?

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Answer:

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Explanation:

Before we solve the question, we have to balance the equation of the reaction first. The balanced reaction will be:

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The answer is 12 N. I hope this helps.

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