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deff fn [24]
3 years ago
9

What two factors determine the density of water in deep currents?

Physics
1 answer:
Alecsey [184]3 years ago
7 0

Answer:

There are two main factors that makeocean water more or less dense than about 1027 kg/m3: the temperature of the water and the salinity of the water.Ocean water gets more dense as temperature goes down. So, the colder the water, the more dense it is. Increasing salinity also increases thedensity of sea water.

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"A uniform cylinder of mass M and radius R is rolling without slipping. The velocity of its center of mass is v. What is the cyl
Goshia [24]

Answer:

Explanation:

Given

mass of cylinder is M

radius R

velocity of center of mass is v

As there is no slipping therefore cylinder will rotate as well as translate

Moment of inertia of cylinder I=\frac{MR^2}{2}

Kinetic Energy of cylinder K.E.=\frac{1}{2}Mv^2

Rotational energy R.E.=\frac{1}{2}I\omega ^2

for rolling

v=\omega \times r

where \omega =angular\ velocity\ of\ cylinder

R.E.=\frac{1}{2}\times \frac{MR^2}{2}\times (\frac{v}{R})^2=\frac{1}{4}Mv^2

Total kinetic Energy =\frac{1}{2}Mv^2+\frac{1}{4}Mv^2=\frac{3}{4}Mv^2

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A block of aluminum had a volume of 17.0 mL and a mass of 45.9g. What is it’s density?
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A pendulum is made by letting a 4 kg mass swing at the end of a string that has a length of 1.5 meter. The maximum angle that th
olga nikolaevna [1]

Answer:

Approximately 7.8\; \rm J.

Explanation:

The change in the gravitational potential energy of the pendulum is directly related to the change in its height.

Refer to the sketch attached. The pendulum is initially at \rm P_2. Its highest point is at P_1. The length of segment \rm BP_2 gives the change in its height.

The lengths of \rm AP_1 and \rm AP_2 are simply the length of the string, 1.5\; \rm m. To find the length of \rm BP_2, start by calculating the length of \rm AB.

\rm AB forms a leg in the right triangle \rm \triangle AP_1B. Besides, it is adjacent to the 30^\circ angle \rm P_1\hat{A}B. Its length would be:

\rm AB = 1.5 \times \cos(30^\circ) \approx 1.30\; \rm m.

The length of \rm BP_2 would thus be

\rm BP_2 = AP_2 - AB = 1.5 - 1.30 \approx 0.20\; \rm m.

The change in gravitational potential energy can be found with the equation

\Delta \mathrm{GPE} = m \cdot g \cdot \Delta h. In this equation,

  • m is the mass of the object,
  • g \approx 9.81\; \rm N \cdot kg^{-1} near the surface of the earth, and
  • \Delta h is the change in the object's height.

In this case, m = 4\; \rm kg and \Delta h \approx 0.20\; \rm m. Therefore:

\Delta \mathrm{GPE} = 4 \times 9.81 \times 0.20 \approx 7.8\; \rm J.

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