The diagram shows a charge moving into an electric field. The charge will most likely leave the electric field near which letter
1 answer:
you haven't attached the diagram, but i assume that this diagram is what you were talking about
Answer:
near Y
Explanation:
the electric field lines goes from a positive charge to a negative charge. This means that a positive charge would move in the same direction of the field lines, while a negative charge would move in the opposite direction of the field lines. the field lines are created from +vely charged plate to -vely charged plate so the negative charged particles moves towards the lower plate which is positively charged, and opposite to the direction of field lines.
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The ratio of their amplitudes will be 2.41.
To find the answer, we have to know more about the simple harmonic motion.
<h3>How to find the ratio of their amplitudes?</h3>- It is given that,
- We have the relation between these quantities and amplitudes as,
- Here, for both the oscillation, k will be same.
- Thus, the ratio of amplitude will be,
Thus, we can conclude that, the ratio of their amplitudes will be 2.41.
Learn more about simple harmonic motion here:
#SPJ4
<u>The answer is not contained detail explanation, just a solution and the required values. </u>
All the details are in the pictures, the answers are marked with orange colour.
Note,
in the task no 20.:
V - the velocity of the pair of the balls after collision.
in the task no 21:
m₁ - the mass of the copper ball; m₂ - the mass of the copper calorimeter; m₃ - the mass of the water; t₀ - the initial temperature of water in the copper calorimeter; θ - the final temperature in the calorimeter after the copper ball is transferred into a copper calorimeter; t₁ - the required initial temperature of the copper ball before it is transferred into the calorimeter.
