The diagram shows a charge moving into an electric field. The charge will most likely leave the electric field near which letter
1 answer:
you haven't attached the diagram, but i assume that this diagram is what you were talking about
Answer:
near Y
Explanation:
the electric field lines goes from a positive charge to a negative charge. This means that a positive charge would move in the same direction of the field lines, while a negative charge would move in the opposite direction of the field lines. the field lines are created from +vely charged plate to -vely charged plate so the negative charged particles moves towards the lower plate which is positively charged, and opposite to the direction of field lines.
You might be interested in
Answer:
w1 = 4.04 / √r
Explanation:
This exercise should be done using Newton's second law, where the centripetal month acceleration, write the equation for the vertical axis and the radius of rotation
Y Axis
fr - W = 0
fr = W
X axis (radial)
N = m
The equation for the force of friction is
fr = μ N
Let's replace
μ (m
) = mg
Centripetal acceleration is
= v² / r
v = wr
= w² r
μ w² r = g
w = √(g/μ r)
In order for the trip to be safe, people must not move, so the friction must be static, let's calculate the angular velocity for the extreme values of the friction increase
μ = 0.60
w1 = √ (9.8 / 0.6 r)
w1 = 4.04 / √r
μ = 1.0
w2 = √ (9.8 / 1 r)
w2 = 3.13 / √r
To finish the calculation you need the radius of the cylinder, but for the same radius the safe speed is w1