Answer:
Explanation:
Brownian motion is a random (irregular) motion of particles e.g smoke particle. The set up in the diagram can be used to observe the motion of smoke.
1. The apparatus used are:
A is a source of light
B is a converging lens
C is a glass smoke cell
D is a microscope
2. The uses of the apparatus are:
A - produces the light required to so as to see clearly the movement of the particles.
B - converges the rays of light from the source to the smoke cell.
C - is made of glass and used for encamping the smoke particles so as not to mix with air.
D - is used for the clear view or observation or study of the motion of the smoke particles in the cell.
The maximum speed of the donkey is 10.72m/s
The question is based on the principle of motion in one dimension and hence formulas of motion in one dimension can be applied.
It is given that donkey attains an acceleration of 1.6 m/s^2
The time taken to accelerate to given speed is 6.7 seconds
We use the formula v=u + at to find the fastest speed
v is the final or maximum speed
u is the initial speed which in this case is 0 as the donkey is at rest
a is the acceleration of the donkey
t is the time taken in seconds
v = u + at
v= 0 + 1.6 x 6.7
= 10.72 m/s
Hence the donkey obtains the speed of 10.72 m/s
For further reference:
brainly.com/question/24478168?referrer=searchResults
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A )
T = mB g + mB a
T + mA a - mA g sin 35° = (Mi) mA g cos 35°
------------------------------------------------------------
T = 2.7 · 9.81 + 2.7 a
T = 26.487 + 2.7 a
26.487 + 2.7 a + 2.7 a - 2.7 · 9.81 · 0.574 = 0.15 · 2.7 · 9.81 · 0.819
5.4 a + 26.487 - 15.2023 = 3.2539
5.4 a = 8.0296
a = 1.487 ≈ 1.5 m/s²
B )
T = 2,7 · 9.81 = 26.487
26.487 - 15.2035 = (Mi) · 2.7 · 9.81 · 0.819
11.2835 = (Mi) · 21.69
(Mi) = 11.2835 : 21.69 = 0.52
Answer:
see the attachment
Explanation:
take coordinate system correctly. use formulas of projectile motion
Answer:
the reaction force in this situation would be B
Explanation:
The action is the wings pushing down whilst the reaction is the air pushing up which allow the bird to fly .
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