A wave has the wavelength equal to 396 nm. what must be the frequency of this wave

Which best describes the energy of a sound wave as it travels through a medium

Solnce55 [7]

C. It depends on the medium

3 0

3 years ago

Please help asap

posledela

Answer:

A

Explanation:

the object's mass determines the speed of the object and its kinetic energy

4 0

3 years ago

Read 2 more answers

Dependent variable and the independent variable is ?

koban [17]

The two main variables in an experiment are the independent and dependent variable. An independent variable is the variable that is changed or controlled in a scientific experiment to test the effects on the dependent variable. A dependent variable is the variable being tested and measured in a scientific

7 0

3 years ago

2 kg steel ball is dropped straight down ont a hard horixontal florr and bounces straight up . the balls speed just before and j

Rainbow [258]

Answer:

$40 \frac{kg*m}{s}$

Explanation:

Impulse-momentum theorem states that impulse is equal to the change of momentum:

$\overrightarrow{J}=\overrightarrow{p}_{f}-\overrightarrow{p}_{i}$ (1)

with pf the final momentum and pi the initial momentum. Knowing that momentum is mass (m) times velocity (1) is:

$\overrightarrow{J}=m \overrightarrow{v}_{f}- m \overrightarrow{v}_{i}$

It's important to note that we're dealing with vector quantities so direction matters. If we choose towards the floor positive direction then the initial velocity is positive and the final velocity is negative, so:

$\overrightarrow{J}=-(2kg)(10\frac{m}{s}) - (2.0kg)(10\frac{m}{s})$

$\overrightarrow{J}=-40 \frac{kg*m}{s}$

So, the impulse delivered to the floor is $40 \frac{kg*m}{s}$

5 0

3 years ago

A gold nucleus (with a radius of 6.5 fm in its rest system, containing 197 protons and neutrons of rest mass 939 MeV/c2 each) is

julia-pushkina [17]

Answer:

$1.9982154567\times 10^{-18}\ kgm/s$

762474.685899 MeV

3.1603639031 fm

Explanation:

v = 0.97 c

c = Speed of light = $3\times 10^8\ m/s$

Relativistic momentum is given by

$p=\dfrac{m_0v}{\sqrt{1-\dfrac{v^2}{c^2}}}\\\Rightarrow p=\dfrac{939\times 10^6\times 1.6\times 10^{-19}\times 0.97\times 3\times 10^8}{\sqrt{1-\dfrac{0.97^2c^2}{c^2}}}\\\Rightarrow p=\dfrac{(939\times 10^6\times 1.6\times 10^{-19})J/c^2\times 0.97c}{\sqrt{1-0.97^2}}\\\Rightarrow p=\dfrac{(939\times 10^6\times 1.6\times 10^{-19})\times 0.97}{c\sqrt{1-0.97^2}}\\\Rightarrow p=\dfrac{(939\times 10^6\times 1.6\times 10^{-19})\times 0.97}{3\times 10^8\times \sqrt{1-0.97^2}}\\\Rightarrow p=1.9982154567\times 10^{-18}\ kgm/s$