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vfiekz [6]
3 years ago
5

Prove that A is idempotent if and only if AT is idempotent. Getting Started: The phrase "if and only if" means that you have to

prove two statements. 1. If A is idempotent, then AT is idempotent. 2. If AT is idempotent, then A is idempotent. STEP 1: Begin your proof of the first statement by assuming that A is idempotent.
Mathematics
1 answer:
Otrada [13]3 years ago
3 0

Answer:

It is proved that A is idempotent if and only if A^T is idempotent.

Step-by-step explanation:

Case-1 : First assume that A is idempotent that is, A^2=A. We have to show by using this (A^T)^2=A^T. So,

(A^T)^2=A^T\times A^T=(A\times A)^T=(A^2)^T=A^T

Thus A^T is idempotent.

Case-2 :

Conversly, assuming A^T is idempotent, thet is,  (A^T)^2=A^T . We have to show A^2=A. So,

A^2=A\times A=(A^T)^T\times(A^T)^T=(A^T\times A^T)^T

=((A^T)^2)^T=(A^T)^T=A

Thus A is idempotent. Hence proved.

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3 years ago
Pls help asap!! pic is shown
dsp73

The points (-5, 1), (-2, 4), (2, 4), and (-5, 1) gives the piecewise defined function as the second option;

g(x) = x + 6, when x < -2

g(x) = x², when -2 ≤ x < 2

g(x) = 6 - x, when x ≥ 2

<h3>How can the correct piecewise defined function be found?</h3>

Parts of the function are:

x < -2

Slope = (4-1)/(-2-(-5)) = 1

Equation is: g(x) - 4 = x - (-2)

g(x) - 4 = x + 2

g(x) = x + 2 + 4 = x + 6

  • g(x) = x + 6

In the region, -2 ≤ x < 2, points on the graph are;

(-2, 4), (0, 0), (2, 4)

The above points corresponds with the function;

  • g(x) = x²

In the region x ≥ 2, we have;

Slope = -1

Equation is: g(x) - 4 = -1×(x - 2) = 2 - x

Therefore;

g(x) = 4+2 - x = 6 - x

  • g(x) = 6 - x

The rule for the piecewise defined function is therefore;

  • g(x) = x + 6, when x < -2
  • g(x) = x², when -2 ≤ x < 2
  • g(x) = 6 - x, when x ≥ 2

The correct option is therefore the second option;

Learn more about piecewise defined functions here:

brainly.com/question/11207865

#SPJ1

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