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Goryan [66]
3 years ago
12

Evaluate the expression for the given values.

Mathematics
2 answers:
elixir [45]3 years ago
8 0

Answer:

3

Step-by-step explanation:

1•5-2

5-2=3

STALIN [3.7K]3 years ago
4 0

Answer:

It is three i just took the test

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6x-1=11 solve equation
marin [14]

Answer:

x = 2

Step-by-step explanation:

6x-1=11

Add 1 to each side

6x-1+1=11+1

6x = 12

Divide by 6

6x/6 = 12/6

x = 2

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What is 23.4 x 0.4 equals
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9.36 is what it equals
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42 is how many groups of 7?
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You divide 42 by 7 which equals 6
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Given: A, B, and C What is the value of X in the matrix equation AX + B = C?
Ksju [112]

Answer:

Option (2)

Step-by-step explanation:

Given expression is, AX + B = C

A=\begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}

B=\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix}

C=\begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}

AX + B = C

AX = C - B

C - B = \begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}-\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix} = \begin{bmatrix}-42+7 & -20+9\\ 5-4 & 4+1\end{bmatrix}

C - B = \begin{bmatrix}-35 & -11\\ 1 & 5\end{bmatrix}

Let  X=\begin{bmatrix}a & b\\ c & d\end{bmatrix}

AX = \begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}\times \begin{bmatrix}a & b\\ c & d\end{bmatrix}

     = \begin{bmatrix}(-3a-4c) & (-3b-4d)\\ a & b\end{bmatrix}

Since AX = C - B

\begin{bmatrix}(-3a-4c) & (-3b-4d)\\ a & b\end{bmatrix}=\begin{bmatrix}-35 & -11\\ 1 & 5\end{bmatrix}

Therefore, a = 1, b = 5

(-3a - 4c) = -35

3(1) + 4c = 35

3 + 4c = 35

4c = 32

c = 8

And (-3b - 4d) = -11

3(5) + 4d = 11

4d = -4

d = -1

Therefore, Option (2). X = \begin{bmatrix}1 & 5\\ 8 & -1\end{bmatrix} will be the answer.

7 0
3 years ago
If anyone knows please help me
pishuonlain [190]

Answer:

Step-by-step explanation:

Standard form of a circle is given by,

(x - a)² + (y - b)² = r²

Here, (a, b) is the center and 'r' is the radius of the circle.

For a circle having center (8, -4) and radius r = 1

Equation of the circle will be,

(x - 8)² + (y + 4)² = 1²

(x - 8)² + (y + 4)² = 1

Option (1) is the answer.

Question (2)

Circle with the center (-1, 0) and a point (2, -4) on it,

Radius of the circle = Distance between the center and the given point on                                         circumference

                                = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

                                = \sqrt{(-1-2)^2+(0+4)^2}

                                = \sqrt{9+16}

                                = 5

Therefore, equation of the circle will be,

(x + 1)² + (y - 0)² = 5²

(x + 1)² + y² = 25

8 0
3 years ago
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