Well what I would do is how much do I have to multiply by to get 150 trees which is 1.5. So now we take the 1.5 and the 2 hour multiply them and now we have 3. 3 hours is your answer
Answer: The answer is (D) ![24x+2.](https://tex.z-dn.net/?f=24x%2B2.)
Step-by-step explanation: Given that there is a rectangle, where length of the rectangle is given by
![\ell=4x+5,](https://tex.z-dn.net/?f=%5Cell%3D4x%2B5%2C)
and width of the rectangle is given by
![b=8x-4.](https://tex.z-dn.net/?f=b%3D8x-4.)
We are to find the perimeter of the rectangle. To do so, we need to add two times length with two times breadth of the rectangle.
Therefore, perimeter is given by
![p=2\ell+2b=2\times(4x+5)+2\times(8x-1)=8x+10+16x-8=24x+2.](https://tex.z-dn.net/?f=p%3D2%5Cell%2B2b%3D2%5Ctimes%284x%2B5%29%2B2%5Ctimes%288x-1%29%3D8x%2B10%2B16x-8%3D24x%2B2.)
Thus, the correct option is (D).
Just do how many minutes are in a hour and do that for 2days but 24 times two
Answer:
A, B, E
Step-by-step explanation:
The attachment shows a graph of the function. It tends to infinity for x going to infinity in either direction. (A, B are true)
The right-side piece is cubic, not quadratic.
The U-shape tells you the function is decreasing on the left side.
The two function definitions have the same value at x=2, so the function has no discontinuities. It is continuous. (E is true)
Answer:
The length of each blue trim is 17.2 inches
Step-by-step explanation:
Given
See attachment for banner
Required
The length of each blue trim
Since all 4 triangles are equal, then the dimension of 1 triangle is:
![Side\ 1 = 10](https://tex.z-dn.net/?f=Side%5C%201%20%3D%2010)
![Side\ 2 = 14](https://tex.z-dn.net/?f=Side%5C%202%20%3D%2014)
The hypotenuse (x) of the triangle blue trim is represented by the blue trim
So:
![x^2 = Side\ 1^2 + Side\ 2^2](https://tex.z-dn.net/?f=x%5E2%20%3D%20Side%5C%201%5E2%20%2B%20Side%5C%202%5E2)
This gives
![x^2 = 10^2 + 14^2](https://tex.z-dn.net/?f=x%5E2%20%3D%2010%5E2%20%2B%2014%5E2)
![x^2 = 100 + 196](https://tex.z-dn.net/?f=x%5E2%20%3D%20100%20%2B%20196)
![x^2 = 296](https://tex.z-dn.net/?f=x%5E2%20%3D%20296)
Take square root
![x = \sqrt{296](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%7B296)
![x = 17.2in](https://tex.z-dn.net/?f=x%20%3D%2017.2in)