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Ierofanga [76]
3 years ago
10

How do the particles in s waves move

Chemistry
1 answer:
Darya [45]3 years ago
3 0
In a surface wave, particles of the medium move up and down as well as back and forth in an overall circular motion. The particles don't actually move closer to shore as the waves pass through. In shallow water close to shore, waves start to drag on the bottom of the water.
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Fill in the blank Cells break down sugar and release ___________ into the plant.
katrin2010 [14]

Answer:

oxygen

Explanation:

8 0
2 years ago
atmospheric pressure at elevations of 8000 feet averages about 0.72 atmospheres. Would a cabin pressurized at 500 mm hg meet fed
NeTakaya

Answer:

Yes, but it must be kept at that value and do not let it to decrease more.

Explanation:

Hello.

In this case, in order to substantiate whether the cabin meet the federal standards, we need to convert the 500 mmHg to atm and compare the result with 0.72 atm by knowing that 1 atm equals 760 mmHg:

500mmHg*\frac{1atm}{760mmHg} \\\\=0.66atm

Thus, since 0.66 atm is 0.06 atm away from the federal standard we can infer that it may meet the federal standard, however, it would not be recommended to let the pressure decrease more than that.

8 0
3 years ago
Another one please help
ladessa [460]
Possibly C or D i wanna say sorry if i’m wrong
4 0
2 years ago
What mass of precipitate forms when 185.5 ml of 0.533 m naoh is added to 627 ml of a solution that contains 15.8 g of aluminum s
Law Incorporation [45]

Answer:

2,57 g of precipitate.

Explanation:

For the reaction:

6 NaOH + Al₂(SO₄)₃ → 2 Al(OH)₃ + 3 Na₂SO₄

The precipitate is Al(OH)₃.

185,5mL of 0,533M NaOH are:

0,1855L × 0,533M = <em>0,0989 moles NaOH</em>

Moles of Al₂(SO₄)₃ are:

15,8g × \frac{1mol}{342,15g} = <em>0,0462 moles Al₂(SO₄)₃</em>

For the total reaction of 0,0989 moles NaOH with Al₂(SO₄)₃ you need:

0,0989moles NaOH × \frac{1molAl_{2}(SO_{4})_{3}}{6 moles NaOH} = <em>0,0165 moles Al₂(SO₄)₃</em>

As you have <em>0,0462 moles Al₂(SO₄)₃ </em>the limiting reactant is NaOH.

0,0989 moles of NaOH produce:

0,0989moles NaOH × \frac{2molAl(OH)_{3}}{6 moles NaOH} = <em>0,0330 moles of Al(OH)₃</em>

These moles are:

0,0330 moles of Al(OH)₃ × (78 g/mol) = <em>2,57 g of Al(OH)₃ ≡ mass of precipitate</em>

<em></em>

I hope it helps!

<em> </em>

3 0
3 years ago
Qué valores rescatas de la labor que realizan los bomberos
sertanlavr [38]

Explanation:

Honor:Cumplimos con nuestros deberes con entusiasmo y entrega. Honradez:Respeto a los demás, coherencia física e intelectual en lo que pertenece a cada persona y convicción de defenderlo. Humanismo:Preocupación por lo social y humano. ... Respeto:Tratar humanamente a las personas.

8 0
2 years ago
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