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3 years ago

Which electron configuration is correct for a sodium ion?

Chemistry

1 answer:

ioda3 years ago

3 0

on the basis of 2n2 rule or subshell?

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In an experiment, zinc chlorate decomposed according to the following chemical equation.

mote1985 [20]

Answer : The correct expression is, (150 × 3 × 31.998) ÷ (232.29 × 1) grams

Explanation :

First we have to calculate the moles of $Zn(ClO_3)_2$

$\text{ Moles of }Zn(ClO_3)_2=\frac{\text{ Mass of }Zn(ClO_3)_2}{\text{ Molar mass of }Zn(ClO_3)_2}=\frac{150g}{232.29g/mole}=\frac{150}{232.29}mole$

Now we have to calculate the moles of $O_2$

The balanced chemical reaction is,

$Zn(ClO_3)_2\rightarrow ZnCl_2+3O_2$

From the balanced chemical reaction we conclude that,

As, 1 mole of $Zn(ClO_3)_2$ react to give 3 mole of $O_2$

So, $\frac{150}{232.29}$ moles of $Zn(ClO_3)_2$ react to give $\frac{150}{232.29}\times \frac{3}{1}$ moles of $O_2$

Now we have to calculate the mass of $O_2$

$\text{ Mass of }O_2=\text{ Moles of }O_2\times \text{ Molar mass of }O_2$

$\text{ Mass of }O_2=(\frac{150}{232.29}\times \frac{3}{1})mole\times (31.998g/mole)=\frac{150\times 3\times 31.998}{232.29\times 1}g$

Therefore, the correct expression for the mass of oxygen gas formed is, (150 × 3 × 31.998) ÷ (232.29 × 1) grams

6 0

3 years ago

Read 2 more answers

Which of the following elements has the lowest first ionizition energy ?

Hatshy [7]

Answer:

I think Mg is correct I am not sure

5 0

3 years ago

Read 2 more answers

During the reaction of molecular bromine with 2,2,3-trimethyl pentane initiated by heat or light hydrogen atom will be abstracte

Romashka-Z-Leto [24]

Answer:carbon number 3 of the parent chain

Explanation:

CH3CH2CH(CH3)C(CH3)2CH3.

Looking at the structural formula of the above compound, the carbon on position 3, in the parent chain is a tertiary carbon atom. The reaction in question proceeds by free radical mechanism. Hydrogen is first abstracted from the carbon atom that leads to te formation of the most stable carbocation. For this reason, hydrogen is abstracted from carbon 3 of the parent chain.

8 0

4 years ago

Select the correct image.

masya89 [10]

Answer:

Explanation:

In all the other options either Carbon has more than 4 atoms attached or less than 4.

Carbon can not form more than four bonds. It can only share 4 electrons .

In other option C, No H-atom is linked in the right most Carbon.

whereas according to the definition of Hydrocarbon it should have been a Hydrogen atom.

3 0

4 years ago

In Part III, the phenolphthalein indicator is used to monitor the equilibrium shifts of the ammonia/ammonium ion system. The phe

AnnZ [28]

The pink color in the solution fades. Some of the colored indicator ion converts to the colorless indicator molecule.

<h3>Explanation</h3>

What's the initial color of the solution?

$\text{NH}_4\text{Cl}$ is a salt soluble in water. $\text{NH}_4\text{Cl}$ dissociates into ions completely when dissolved.

$\text{NH}_4\text{Cl} \; (aq)\to {\text{NH}_4}^{+} \; (aq) +{\text{Cl}}^{-} \; (aq)$ .

The first test tube used to contain $\text{NH}_4\text{OH}$ . $\text{NH}_4\text{OH}$ is a weak base that dissociates partially in water.

$\text{NH}_4\text{OH} \; (aq) \rightleftharpoons {\text{NH}_4}^{+} \;(aq)+ {\text{OH}}^{-} \; (aq)$ .

There's also an equilibrium between $\text{OH}^{-}$ and ${\text{H}_3\text{O}}^{+}$ ions.

${\text{OH}}^{-}\;(aq) + {\text{H}_3\text{O}}^{+} \;(aq) \to 2\; \text{H}_2\text{O} \;(l)$ .

$\text{OH}^{-}$ ions from $\text{NH}_4\text{OH}$ will shift the equilibrium between $\text{OH}^{-}$ and ${\text{H}_3\text{O}}^{+}$ to the right and reduce the amount of ${\text{H}_3\text{O}}^{+}$ in the solution.

The indicator equilibrium will shift to the right to produce more ${\text{H}_3\text{O}}^{+}$ ions along with the colored indicator ions. The solution will show a pink color.

What's the color of the solution after adding NH₄Cl?

Adding $\text{NH}_4\text{Cl}$ will add to the concentration of ${\text{NH}_4}^{+}$ ions in the solution. Some of the ${\text{NH}_4}^{+}$ ions will combine with $\text{OH}^{-}$ ions to produce $\text{NH}_4\text{OH}$ .

The equilibrium between $\text{OH}^{-}$ and ${\text{H}_3\text{O}}^{+}$ ions will shift to the left to produce more of both ions.

${\text{OH}}^{-}\;(aq) + {\text{H}_3\text{O}}^{+} \;(aq) \to 2\; \text{H}_2\text{O} \;(l)$

The indicator equilibrium will shift to the left as the concentration of ${\text{H}_3\text{O}}^{+}$ increases. There will be less colored ions and more colorless molecules in the test tube. The pink color will fade.

7 0

4 years ago