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4 years ago

HELP PLEASE What about winter temperatures of 0 and -3? …………….% 28 and 15? ……………….%

Chemistry

1 answer:

Ymorist [56]4 years ago

6 0

Answer:

45 and 12

Explanation:

- I am concerned with the question, as -3 is not possible to do on your chart or any other chart. The only other possible numbers could be 0 and 3, which give you 45.

- The second problem look at 28 on left hand side and 15 on top. Meet those in the middle and you get 12.

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49.9 ml of a 0.00292 m stock solution of a certain dye is ddiluted to 1.00 L. the diluted solution has an absorbance of 0.600. w

inna [77]

Complete Question

49.9 ml of a 0.00292 m stock solution of a certain dye is diluted to 1.00 L. the diluted solution has an absorbance of 0.600. what is the molar absorptivity coefficient of the dye

Answer:

The value is $\epsilon = 4118.1 \ M^{-1} cm^{-1}$

Explanation:

From the question we are told that

The volume of the stock solution is $V_1 = 49.9 mL = 0.0499 \ L$

The concentration of the stock solution is $C_1 = 0.00292 \ M$

The volume of the diluted solution is $V_2 = 1.00 \ L$

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Generally the from the titration equation we have that

$C_1 * V_1 = C_2 * V_2$

=> $0.00292 * 0.0499 = C_2 * 1$

=> $C_2 = 0.0001457 \ M$

Generally from Beer's law we have that

$A = \epsilon * l * C_2$

=> $\epsilon = \frac{A}{ l * C_2 }$

Here l is the length who value is 1 cm because the unit of molar absorptivity coefficient of the dye is $M^{-1} * cm^{-1}$

$\epsilon = \frac{0.600}{ 1 * 0.0001457 }$

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