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Nat2105 [25]
3 years ago
15

What would the formula of an ionic compound made of Aluminum and Oxygen be?

Chemistry
1 answer:
yan [13]3 years ago
8 0

Answer:

Sodium Aluminate

Formula:-

\quad{:}\longrightarrow\sf NaAlO_2

<h3><u>Explore</u><u> </u><u>more</u><u>:</u><u>-</u></h3>

Melting points and boiling points of some ionic compounds

\boxed{\begin{array}{|c|c|c|c|} \cline {1-4}\Large\sf {Ionic\:Compounds} & \sf \Large {Chemical\:Formula} & \Large \sf{Melting\:point_{(k)}} & \Large\sf {Boiling\:point_{(k)}} \\ &&& \\ \cline {1-4} \sf Sodium\:Chloride & \sf NaCl & 1074 & 1686 \\ &&& \\ \cline {1-4} \sf Lithium\:Chloride & \sf \sf LiCl & 887 & 1600 \\ &&& \\ \cline {1-4} \sf Calcium\:Chloride & \sf CaCl_2 & 1045 & 1900 \\ &&& \\ \cline {1-4} \sf Calcium\:Oxide & \sf CaO & 2850 & 3120 \\ &&& \\ \cline {1-4} \sf Magnesium\:Chloride & \sf MgCl_2 & 981 & 1685 \\ &&& \\ \cline {1-4} \end{array}}

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kiruha [24]
About 75% of earth’s surface is covered by the ocean
4 0
3 years ago
Read 2 more answers
What is the volume of 40g of sugar given it’s listed density
lora16 [44]

Answer:

25.157 cm³

Explanation:

Data Given:

Mass of Sugar (m) = 40g

Density of sugar given in literature = 1.59 g/cm³

Volume of Sugar = ?

The formula will be used is

                              d = m/v ........................................... (1)

where

D is density

m is the mass

v is the volume

So

Rearrange the Equation (1)

                              d x v = m

                               v = m/ d         ................................................ (2)

put the given values in Equation  (2)

                       v = 40g / 1.59 g/cm³

                       v = 25.157 cm³

volume of 40 g of sugar = 25.157 cm³

8 0
3 years ago
The graph shows the changes in the phase of ice when it is heated.
kow [346]

Answer:

A) 0 °C, because it is the melting point of ice.

Explanation:

  • Point B is the temperature at which the water is converted from ice (solid phase) to liquid water (liquid phase), which is the melting transition of water.

Melting point of the water is at 0.0°C.

<em>So, the right choice is: A) 0 °C, because it is the melting point of ice. </em>

<em></em>

6 0
3 years ago
Read 2 more answers
Can I get help with this, please!!
kondor19780726 [428]

Pressure in the submarine when the temperature is changed to 293 K is 108.9 K Pa

Explanation:

Pressure in the submarine = 108.9 kPa

Volume, V = 2.4 * 10^5 L

Pressure, P = 116k Pa

Temperature, T = 312 K

Ideal gas law: PV = nRT  or  n = PV / RT

So, moles of gas, n =116 KPa * 2.4 * 10 ^5L / 8.314 LK Pa K^-1 *312 K

= 1.073 *10^4 mol

when temperature is changed to 293K,

PV = nRT  or P = nRT / V

=1.073 *10^4 mol *8.314 LK Pa mol^-1 K^-1 *293 K / 2.4*10^5L

=108.9 K Pa

Pressure in the submarine when the temperature is changed to 293 K is 108.9 K Pa

8 0
3 years ago
Suppose a 0.025M aqueous solution of sulfuric acid (H2SO4) is prepared. Calculate the equilibrium molarity of SO4−2. You'll find
FromTheMoon [43]

<u>Answer:</u> The concentration of SO_4^{2-} at equilibrium is 0.00608 M

<u>Explanation:</u>

As, sulfuric acid is a strong acid. So, its first dissociation will easily be done as the first dissociation constant is higher than the second dissociation constant.

In the second dissociation, the ions will remain in equilibrium.

We are given:

Concentration of sulfuric acid = 0.025 M

Equation for the first dissociation of sulfuric acid:

       H_2SO_4(aq.)\rightarrow H^+(aq.)+HSO_4^-(aq.)

            0.025          0.025       0.025

Equation for the second dissociation of sulfuric acid:

                    HSO_4^-(aq.)\rightarrow H^+(aq.)+SO_4^{2-}(aq.)

<u>Initial:</u>            0.025            0.025      

<u>At eqllm:</u>      0.025-x          0.025+x        x

The expression of second equilibrium constant equation follows:

Ka_2=\frac{[H^+][SO_4^{2-}]}{[HSO_4^-]}

We know that:

Ka_2\text{ for }H_2SO_4=0.01

Putting values in above equation, we get:

0.01=\frac{(0.025+x)\times x}{(0.025-x)}\\\\x=-0.0411,0.00608

Neglecting the negative value of 'x', because concentration cannot be negative.

So, equilibrium concentration of sulfate ion = x = 0.00608 M

Hence, the concentration of SO_4^{2-} at equilibrium is 0.00608 M

4 0
3 years ago
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