Question

What would the formula of an ionic compound made of Aluminum and Oxygen be?

Answer 1

Answer:

Sodium Aluminate

Formula:-

$\quad{:}\longrightarrow\sf NaAlO_2$

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Melting points and boiling points of some ionic compounds

$\boxed{\begin{array}{|c|c|c|c|} \cline {1-4}\Large\sf {Ionic\:Compounds} & \sf \Large {Chemical\:Formula} & \Large \sf{Melting\:point_{(k)}} & \Large\sf {Boiling\:point_{(k)}} \\ &&& \\ \cline {1-4} \sf Sodium\:Chloride & \sf NaCl & 1074 & 1686 \\ &&& \\ \cline {1-4} \sf Lithium\:Chloride & \sf \sf LiCl & 887 & 1600 \\ &&& \\ \cline {1-4} \sf Calcium\:Chloride & \sf CaCl_2 & 1045 & 1900 \\ &&& \\ \cline {1-4} \sf Calcium\:Oxide & \sf CaO & 2850 & 3120 \\ &&& \\ \cline {1-4} \sf Magnesium\:Chloride & \sf MgCl_2 & 981 & 1685 \\ &&& \\ \cline {1-4} \end{array}}$