PART A:
The generic equation of the line is:
y-yo = m (x-xo)
First we look for the slope of the line:
m = (y2-y1) / (x2-x1)
m = ((5000) - (6000)) / (4-3)
m = -1000
Then, we substitute any point in the generic equation:
(xo, yo) = (4, 5000)
Substituting:
y-5000 = (- 1000) (x-4)
Rewriting:
y = -1000x + 4000 + 5000
y = -1000x + 9000
The equation is:
y = -1000x + 9000
PART B:
For the price of 3.50 we have:
y = -1000 * (3.5) +9000
y = 5500
Answer: (Mayadc821 wrote this anwser check theyre account for more)
Since you know the x and y values, you just have to plug these into the linear slope-intercept equation:
y = mx + b
-10 = m(1) + b
m + b = -10
b = -10 - m
Now that we have a value for b, we can plug this into the other equation:
8 = m(-8) + b
8 = -8m + (-10 - m)
8 = -9m -10
18 = -9m
m = -2
Now that we know what m is equal to, we can plug this into our first equation to get an answer for b:
b = -10 - m
b = -10 -(-2)
b = -10 + 2
b = -8
Our final equation is y = -2x - 8
Answer:
The last choice is the one you want
Step-by-step explanation:
First of all, a parabola has a minimum value if it is a positive parabola, one that opens upward. The first and the third parabolas are negative so they open upside down. That leaves us with choices 2 and 4. We find the side to side and up or down movement by finishing the completion of the square that has already been started for us. Do this by factoring what's inside the parenthesis into a perfect square binomial.
The second one factored becomes:
![g(x)=4(x-3)^2+1](https://tex.z-dn.net/?f=g%28x%29%3D4%28x-3%29%5E2%2B1)
which reflects a shift to the right 3 and up 1. Not what we are asked to find.
The fourth one factored becomes:
![g(x)=8(x-3)^2-5](https://tex.z-dn.net/?f=g%28x%29%3D8%28x-3%29%5E2-5)
which reflects a shift to the right 3 and down 5. That's what we want!
Answer:
Missing Value Is 4 .
Step-by-step explanation:
According To The Question, We Have
- A model with 4rows*4squares & 4rows*7squares
Equation is 16+28 = X*(4+7)
Solve the above Equation, We get 44=X*11 ⇔ X=4