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Norma-Jean [14]
3 years ago
8

Please help me with all I need for tomorrow thanks

Mathematics
1 answer:
Vikentia [17]3 years ago
3 0
1. 6
2. 4
3. 5
4. area
5. perimeter
6. 12
7. 16

8.

   .   . _ . _ ._.   .   .
   .   |.   .   .   |._.   .
   .   |.   .   .   .   |.  .
   .   |.   .   .   . _|.   .
   .   |. _. _. _|.   .   .

Area = 14

The borders enclose 14 squares that are 1 long and 1 unit wide.
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If two lines l and m are parallel, then a reflection along the line l followed by a reflection along the line m is the same as a
Veseljchak [2.6K]
Answer b is correct for this Question
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What is the greatest possible product of a 2 digit number and a 1 digit number?
sladkih [1.3K]
Highest 2-digit number = 99 
<span>Highest 1-digit number = 9 </span>
<span>Highest possible sum from 2, 2-digit numbers = 198 </span>
<span>Highest possible sum from 2, 1-digit numbers = 18</span>
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Sorry for the quality but please help?!?!
gogolik [260]

Answer:

3/4

Step-by-step explanation:

28 total but 12 are boys so girls = 28 - 12 = 16

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= 12/16

= 3/4

6 0
3 years ago
The number of phone calls between two​ cities, N, during a given time period varies directly as the populations p 1 and p 2 of t
kherson [118]

Answer:

∴73,563 calls are made between two cities with populations of 100,000 and 160,000 that are 435 miles apart.

Step-by-step explanation:

Given that,

The number of phone calls between two cities (N )

  • directly proportional as the value of populations p_1  and p_2  of two cities.
  • Inversely varies as the magnitude of distance (d).

N\propto\frac{p_1p_2}{d}

N=k.\frac{p_1p_2}{d}

Given that,

N=18,000, d=310 miles,  p_1=15,500 and p_2=180,000

18,000=k.\frac{15,500\times 180,000}{310}

\Rightarrow k=\frac{18,000\times310}{15,500\times 180,000}

\Rightarrow k=\frac{31}{15,500}

Now,

N=? , d=435 miles,  p_1=100,500 and p_2=160,000

N=\frac{31}{15,500}.\frac{100,000\times 160,000}{435}

\Rightarrow N\approx 73,563

∴73,563 calls are made between two cities with populations of 100,000 and 160,000 that are 435 miles apart.

5 0
3 years ago
How many four-character alpha-numeric codes are possible if repeated characters are not allowed?
sweet [91]

Answer:

1,413,720

Step-by-step explanation:

Total number of characters = letters + numbers

= 26 + 10

= 36.

So total number of possible codes

= 36P4

=  36!/ (36-4)!

= 36*35*34*33

= 1413720

5 0
3 years ago
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