Explanation:
In gases the molecules are held together by weak Vander waal forces. Due to this they have more kinetic energy and they tend to diffuse at a faster rate because of more number of collisions between the molecules.
That is why, its molecules readily spread into the atmosphere as compared to the molecules of solids and liquids. Also, when molecules of a gas collide with the walls of a container then they tend to come back at their initial position for a fraction of second or more.
Hence, gas collisions are elastic in nature.
According to Graham's law, rate of diffusion of a gas is inversely proportional to the square root of molar mass of the gas. Hence, more is the molecular weight of gas less likely it is able to diffuse into the surroundings.
Thus, we can conclude that following apply to gases.
- Gas collisions are elastic.
- Gases mix faster than solids or liquids.
- Gases with larger molecular weights diffuse slower than gases with lower molecular weights.
Answer:
0.238 M
Explanation:
A 17.00 mL sample of the dilute solution was found to contain 0.220 M ClO₃⁻(aq). The concentration is an intensive property, so the concentration in the 52.00 mL is also 0.220 M ClO₃⁻(aq). We can find the initial concentration of ClO₃⁻ using the dilution rule.
C₁.V₁ = C₂.V₂
C₁ × 24.00 mL = 0.220 M × 52.00 mL
C₁ = 0.477 M
The concentration of Pb(ClO₃)₂ is:
RMM of CaH2=20+(1x2)=22
Number of moles or formula units
=mass/RMM
=8.294/22
=0.377
Answer:
a) The work done is 10.0777 kJ
b) The water's change in internal energy is -122.1973 kJ
Explanation:
Given data:
1 mol of liquid water
T₁ = temperature = 100.9°C
P = pressure = 1 atm
Endothermic reaction
T₂ = temperature = 100°C
1 mol of water vapor
VL = volume of liquid water = 18.8 mL = 0.0188 L
VG = volume of water vapor = 30.62 L
3.25 moles of liquid water vaporizes
Q = heat added to the system = -40.7 kJ
Questions: a) Calculate the work done on or by the system, W = ?
b) Calculate the water's change in internal energy, ΔU = ?
Heat for 3.25 moles:
The work done:
The change in internal energy:
M(Cs)=133 g/mol
M(O)=16 g/mol
M(CsxOy)=298 g/mol
w(Cs)=0.89
w(O)=0.11
CsxOy
x=M(CsxOy)w(Cs)/M(Cs)
x=298*0.89/133=2
y=M(CsxOy)w(O)/M(O)
y=298*0.11/16=2
Cs₂O₂ cesium peroxide
