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bulgar [2K]
1 year ago
7

Given the following list of densities, which materials would float in a molten vat of lead provided that they do not themselves

melt? Densities: g/mL: lead= 11.4; glass= 2.6, gold= 19.3, charcoal= 0.57, platinum = 21.4. Enter your answer as a word only. If two or more items would float include the word and between those two items.
Chemistry
1 answer:
Nataly [62]1 year ago
7 0

The materials that would float in a molten vat of lead are glass and charcoal.

<h3>Which material floats on the solution?</h3>

Glass and charcoal are the materials that would float in a molten vat of lead because they are less denser than the lead solution while on the other hand, platinum and gold get drowned into the solution because of its high density as compared to lead.

So we can conclude that the materials that would float in a molten vat of lead are glass and charcoal.

Learn more about density here: brainly.com/question/14997726

#SPJ1

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Katena32 [7]

Answer:

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6 0
3 years ago
How much pressure would 0.8 moles of a gas at 370K exert if it occupied 17.3L of space
dezoksy [38]

Answer:

1.40 atm is the pressure for the gas

Explanation:

An easy problem to solve with the Ideal Gases Law:

P . V = n . R .T

T° = 370K

V = 17.3L

n = 0.8 mol

Let's replace data → P . 17.3L = 0.8mol . 0.082L.atm/mol.K . 370K

P = (0.8mol . 0.082L.atm/mol.K . 370K) / 17.3L = 1.40 atm

7 0
3 years ago
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Write balanced chemical equations for the sequence of reactions that oxalic acid can undergo when it's dissolved in water.
Mashcka [7]

Answer and Explanation:

The balanced chemical equations are as follows:

The chemical formula of oxalic is  H_2C_2O_4

In the case when oxalic acts reacted with the water so here the oxalic acid eliminates one proton that leads to the development of mono acids

After that, the second step derives that when oxalic acid is in aqueous solution eliminates other proton so it represent the polyprotic acid

Now the chemical equations are as follows:

Elimination of one proton

H_2C_2O_4(aq)+H_2O(l)  \rightarrow H_2C_2O_4^-(aq) + H_3O^+(aq)

Now the elimination of other proton

HC_2O_4^-(aq)+H_2O(l)  \rightarrow C_2O_4^2^-(aq) + H_3O^+(aq)

7 0
2 years ago
How many moles in 6.57 x 10^24 formula units of NaCl?
laiz [17]

Answer:

3.955*10^48

Explanation:

1 mole of a substance gives 6.02*10^23/6.57*10^24 will give x then cross multiply the answer. is 3.955*10^48

8 0
3 years ago
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Reptile [31]
Primary treatment !(:


8 0
3 years ago
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