The electron dot diagram for the oxygen atom shows six electrons around the symbol of the atom.
<h3>What is the electron dot diagram?</h3>
The electron dot diagram is the diagram of atoms of elements showing only the valence electrons present in the atom represented with dots.
The electron dot diagram for the oxygen atom is drawn as follows:
- The number of valence electrons in oxygen atom is determined; valence electrons = 6
- The symbol for the oxygen atom is written
- The valence electrons are shown as dots around the symbol of the element.
In conclusion, the electron dot diagram uses dots around the symbol of an atom to show the valence electrons in the atom.
Learn more about electron dot diagram at: brainly.com/question/5835591
#SPJ1
The equilibrium constant of the reaction is 282. Option D
<h3>What is equilibrium constant?</h3>
The term equilibrium constant refers to the number that often depict how much the process is able to turn the reactants in to products. In other words, if the reactants are readily turned into products, then it follows that the equilibrium constant will be large and positive.
Concentration of bromine = 0.600 mol /1.000-L = 0.600 M
Concentration of iodine = 1.600 mol/1.000-L = 1.600M
In this case, we must set up the ICE table as shown;
Br2(g) + I2(g) ↔ 2IBr(g)
I 0.6 1.6 0
C -x -x +2x
E 0.6 - x 1.6 - x 1.190
If 2x = 1.190
x = 1.190/2
x = 0.595
The concentrations at equilibrium are;
[Br2] = 0.6 - 0.595 = 0.005
[I2] = 1.6 - 0.595 = 1.005
Hence;
Kc = [IBr]^2/[Br2] [I2]
Kc = ( 1.190)^2/(0.005) (1.005)
Kc = 282
Learn more about equilibrium constant:brainly.com/question/15118952
#SPJ1
The answer is D. Heterogeneous mixture
Answer:
What is the net ionic equation for a reaction between HCl and NaOH?
Explanation:
A salt is a neutral ionic compound. Let's see how a neutralization reaction produces both water and a salt, using as an example the reaction between solutions of hydrochloric acid and sodium hydroxide. The overall equation for this reaction is: NaOH + HCl → H2O and NaCl
Hope that helped.
Shgehebrhdudhduhfhdurvrudveuevsueveuevege
