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3 years ago

Which of the following pairs of aqueous solutions will form a precipitate when mixed?

1 answer:

4 0

I think the correct answer from the choices listed above is option B. The reactants calcium sulfide and sodium sulfate will react and form a precipitate which is calcium sulfate since it is only slightly soluble in aqueous solution. Hope this answers the question.

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4.00 moles of CU(CN)2<br><br>Find the number of grams

UNO [17]

Hey there!

Cu(CN)₂

Find the molar mass.

Cu: 1 x 63.546 = 63.546

C: 2 x 12.01 = 24.02

N: 2 x 14.07 = 28.14

-----------------------------------

115.706 grams

The mass of one mole of Cu(CN)₂ is 115.706 grams.

We have 4 moles.

115.706 x 4 = 463

4.00 moles of Cu(CN)₂ has a mass of 463 grams.

Hope this helps!

6 0

3 years ago

Fe (s) + S (I) --> Fes (s) In the experiment above, 7.62 g of Fe

Natali [406]

Answer:

Explanation:

calculation

6 0

2 years ago

In solid NaCl, the equilibrium separation between neighboring Na+ and Cl- ions is 0.283 nm. Calculate the coulombic energy betwe

const2013 [10]

Explanation:

It is given that r = 0.283 nm. As 1 nm = $10^{-9} m$ .

Hence, 0.283 nm = $0.283 \times 10^{-9} m$

Formula for coulombic energy is as follows.

$U_{coulomb} = -1.748 \frac{e^{2}}{4 \pi \epsilon_{o} r}$

where, e = $1.6 \times 10^{-19}$ C

$\epsilon_{o}$ = $8.85 \times 10^{-12}$

$U_{coulomb} = -1.748 \frac{(1.6 \times 10^{-19}^{2}}{4 \times 3.14 \times 8.85 \times 10^{-12} \times 0.283 \times 10^{-9}}$

= $1.423 \times 10^{-18} J$

As 1 eV = $1.6 \times 10^{-19} J$

So, 1 J = $\frac{1 eV}{1.6 \times 10^{-19}}$

Hence, U = $\frac{1.423 \times 10^{-18} J}{1.6 \times 10^{-19} J}$

= 8.9 eV

Also, 1 J = $\frac{10^{-3} kJ}{6.022 \times 10^{23}mol}$

= $1.67 \times 10^{-27}$ kJ/mol

Therefore, U = $1.423 \times 10^{-18} J \times 1.67 \times 10^{-27}$ kJ/mol

= $2.37 \times 10^{-45} kJ/mol$

7 0

3 years ago

Why is pyridine included in the reaction of an acid chloride and an amine or alcohol? Pyridine will deprotonate the amine or alc

Pavel [41]

Answer:

Pyridine will neutralize the acid by-product of the reaction.

Explanation:

In the esterifications, hydrochloric acid is released as a by-product that reacts directly with the pyridine in the medium to give the pyridine hydrochloride.

7 0

3 years ago

Give 10 chemical properties of common polymers

algol [13]

Answer:

Some of the useful properties of various engineering polymers are high strength or modulus to weight ratios (light weight but comparatively stiff and strong), toughness, resilience, resistance to corrosion, lack of conductivity (heat and electrical), color, transparency, processing, and low cost

Explanation:

3 0

3 years ago

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