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2 years ago

Most oxygen in our atmosphere _____. has a single oxygen atom combines with carbon has two oxygen atoms has three oxygen atoms

Physics

1 answer:

andrew-mc [135]2 years ago

5 0

Answer:

Two oxygen atoms

Explanation:

The majority of the oxygen in the air in our atmosphere consists of molecular oxygen ( $O_2$ ), which consists of 2 atoms of oxygen, since free oxygen mainly form covalent bonds with other atoms of oxygen.

A small fraction of the oxygen, however, in the ozone form, which consists of 3 atoms of oxygen bond together ( $O_3$ ).

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marishachu [46]

Answer:

constant at the speed of light

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3 years ago

Help with physics projectile motion

BlackZzzverrR [31]

Answer:

10.4 m/s

Explanation:

First, find the time it takes for the projectile to fall 6 m.

Given:

y₀ = 6 m

y = 0 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: t

y = y₀ + v₀ t + ½ at²

(0 m) = (6 m) + (0 m/s) t + ½ (-9.8 m/s²) t²

t = 1.11 s

Now find the horizontal position of the target after that time:

Given:

x₀ = 6 m

v₀ = 5 m/s

a = 0 m/s²

t = 1.11 s

Find: x

x = x₀ + v₀ t + ½ at²

x = (6 m) + (5 m/s) (1.11 s) + ½ (0 m/s²) (1.11 s)²

x = 11.5 m

Finally, find the launch velocity needed to travel that distance in that time.

Given:

x₀ = 0 m

x = 11.5 m

t = 1.11 s

a = 0 m/s²

Find: v₀

(11.5 m) = (0 m) + v₀ (1.11 s) + ½ (0 m/s²) (1.11 s)²

v₀ = 10.4 m/s

3 0

3 years ago

Why do different substances have different melting and boiling points?

azamat

Because the atoms and molecules all have different properties

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2 years ago

A cat leaps into the air to catch a bird with an initial speed of 2.74 m/s at an angle of 60.0° above the ground. What is the hi

Volgvan

Answer: D. 0.29 m

Explanation:

We will use the following equations to describe the leap of the cat:

$y=V_{o}sin\theta t-\frac{gt^{2}}{2}$ (1)

$V_{y}=V_{oy}-gt$ (2)

Where:

$y$ is the height of the cat

$V_{oy}=V_{o}sin\theta$ is the cat's initial velocity

$\theta=60\°$

$g=9.8m/s^{2}$ is the acceleration due gravity

$t$ is the time

$V_{y}$ is the y-component of the velocity

Now the cat will have its maximum height $y_{max}$ when $V_{y}=0$ . So equation (2) is rewritten as:

$0=V_{oy}-gt$ (3)

Finding $t$ :

$t=\frac{V_{oy}}{g}=\frac{V_{o}sin\theta}{g}$ (4)

$t=\frac{2.74 m/s sin(60\°)}{9.8m/s^{2}}$ (5)

$t=0.24 s$ (6)

Substituting (6) in (1):

$y_{max}=(2.74 m/s)sin(60\°) (0.24 s)-\frac{(9.8m/s^{2})(0.24 s)^{2}}{2}$ (7)

Finally:

$y_{max}=0.287 m \approx 0.29 m$ (8)

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3 years ago

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bixtya [17]

1200 watt seconds
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2 years ago