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rosijanka [135]
3 years ago
14

Which substances will make a salt when combined?

Physics
1 answer:
Phoenix [80]3 years ago
6 0
The answer is A, vinegar and soda. Let me know if you need an explanation :)
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A student tries to produce notes of higher frequency by blowing a trumpet harder. he will succeed?​
sdas [7]

Answer:

Please mark as Brainliest!!

Explanation:

He will not succeed as it blows the trumpet harder that only increase the amplitude of the sound wave that means the intensity of the sound will increase but the frequency remains the same.

7 0
2 years ago
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A sort of "projectile launcher" is shown below. A large current moves in a closed loop composed of fixed rails, a power supply,
Zarrin [17]

Answer:

wallah i don't understand anything with my stoopid brain

Explanation:

3 0
2 years ago
How much force does it take to bring a 1,375 N car from rest to a velocity of 26 m/s in 6 seconds?
V125BC [204]

Explanation:

<u>Mass of car</u> = 137.5 kg

<u>Acceleration</u> = v - u / t = 26 - 0 / 6 = 4.33 m/sec^2

Force = m * a = 137.5 * 4.33 = 595.3 N

6 0
3 years ago
BEST ANSWER GETS BRAINLIEST!!!!!!!!!!
denis-greek [22]

Answer:

There are Microwaves, the type of electro magnetic radiation is a Micro-wave. We use x-rays, the type of electro magnetic radiation is a gamma wave. We also use radios, the type of electro magnetic radiation is a radio wave.

Explanation:

I remember doing this assignment too

8 0
2 years ago
A net force of –8750N is used to stop of 1250.kg car travelling 25m/s. What braking distance is needed to bring the car to a hal
Karolina [17]

Answer:

d = 44.64 m

Explanation:

Given that,

Net force acting on the car, F = -8750 N

The mass of the car, m = 1250 kg

Initial speed of the car, u = 25 m/s

Final speed, v = 0 (it stops)

The formula for the net force is :

F = ma

a is acceleration of the car

a=\dfrac{F}{m}\\\\a=\dfrac{-8750}{1250}\\\\a=-7\ m/s^2

Let d be the breaking distance. It can be calculated using third equation of motion as :

v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{0^2-(25)^2}{2\times (-7)}\\\\d=44.64\ m

So, the required distance covered by the car is 44.64 m.

4 0
3 years ago
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