Easy point...

Physics

2 answers:

ad-work [718]2 years ago

6 0

Answer:

At the centre of Earth, the force due to upper half of the Earth will cancel the force due to lower half. In the similar manner, force due to any portion of the Earth at the centre will be cancelled due to the portion opposite to it. Thus, the gravitational force at the centre on any body will be 0.

Explanation:

max2010maxim [7]2 years ago

5 0

Let's see why g is 0 at centre of earth

$\\ \rm\rightarrowtail g\propto \dfrac{1}{h}$

Means g is indirectly proportional to height of object.

If height is more gravity is less
If height is less gravity is more

At centre h=0

So if height is 0 then gravity is also zero.

And at centre the distance from top of earth surface is equal in opposite directions from centre.

$\\ \rm\rightarrowtail F_{net}=0$

So gravity remains 0

You might be interested in

A wave seen at the ocean’s shore is which kind of wave?

Lostsunrise [7]

B. Transverse Wave this is the correct answer

3 0

3 years ago

Read 2 more answers

Un puente de acero de 100 m de largo a 8° C aumenta su temperatura a 24°C ¿Cuánto medirá su longitud? Valor del coeficiente de d

BartSMP [9]

La longitud final del puente de acero es 100.018 metros.

Asumamos que la dilatación térmica experimentada por el puente de acero es pequeña, de modo que podemos emplear la siguiente aproximación lineal para determinar la longitud final del puente de acero ( $L$ ), en metros:

$L = L_{o}\cdot [1+\alpha\cdot (T_{f}-T_{o})]$ (1)

Donde:

$L_{o}$ - Longitud inicial del puente, en metros.
$\alpha$ - Coeficiente de dilatación, sin unidad.
$T_{o}$ - Temperatura inicial, en grados Celsius.
$T_{f}$ - Temperatura final, en grados Celsius.

Si tenemos que $L_{o} = 100\,m$ , $\alpha = 11.5\times 10^{-6}$ , $T_{o} = 8\,^{\circ}C$ y $T_{f} = 24\,^{\circ}C$ , entonces la longitud final del puente de acero es: