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2 years ago

As long as narcotics are prescribed by a doctor, their use will not lead to addiction.

2 answers:

azamat2 years ago

6 0

The correct answer is B. False.

Narcotics have various use in the human body. No matter if the purpose of their use is killing pain, helping the patient to fall asleep easier, or helping the patient battle depression, there is always some danger in using them. Even though they have a different effect from drugs like cocaine and heroine, there are ingredients in many doctor-prescribed narcotics and medications who can lead to some sort of an addiction. In addition, lets not forget that the doctor cannot control how many pills are being taken per day.

stealth61 [152]2 years ago

3 0

False. We can develop an addiction to anything. It doesn't have to be drugs. Nothing in greater amounts is good.

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How much potential energy an object has depends on the object

riadik2000 [5.3K]

Yea you’re right. You answered your own question lol

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3 years ago

9. Which of the following is true?

wlad13 [49]

The answer should be C

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3 years ago

For the reaction shown, calculate how many grams of oxygen form when each quantity of reactant completely reacts.

Nikolay [14]

Explanation:

Molar mass of $KClO_{3}$ = 39.1 + 35.5 + 3(16.0) = 122.6 g

Molar mass of KCl = 39.1 + 35.5 = 74.6 g

Molar mass of $O_{2}$ = 32.0 g

According to the equation, 2 moles of $KClO_{3}$ reacts to give 3 moles of oxygen.

Therefore, 2 (122.6) = 245.2 g of $KClO_{3}$ will give 3 (32.0) = 96.0 g of oxygen. Thus, 245.2 g of $KClO_{3}$ gives 96.0 g of oxygen.

(a) Calculate the amount of oxygen given by 2.72 g of $KClO_{3}$ as follows.

$\frac {96g}{245.2g} \times 2.72 g = 1.06 g$ of $O_{2}$

(b) Calculate the amount of oxygen given by 0.361 g of $KClO_{3}$ as follows.

$\frac {96g}{245.2g} \times 0.361 g = 0.141 g$ of $O_{2}$

c) Calculate the amount of oxygen given by 83.6 kg $KClO_{3}$ as follows.

$\frac {96g}{245.2g} \times 83.6 g = 32.731 kg$ of $O_{2}$

Convert kg into grams as follows.

$\frac{32.731 kg}{1 kg} \times 1000 g$ = 32731 g of $O_{2}$

(d) Calculate the amount of oxygen given by 22.5 mg of $KClO_{3}$ as follows.

$\frac {96g}{245.2g} \times 22.5 mg = 8.79 mg$

Convert mg into grams as follows.

$\frac{8.79 mg}{1 mg}\times 10^{-3} g = 8.79 \times 10^{-3} g$ of $O_{2}$

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3 years ago

Drag the types of electromagnetic waves to place them in order of increasing wavelength.

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3 years ago

Read 2 more answers

what modifications to either or both of the half-cell reactions would kim need to make if she wanted to use them to produce equa

kompoz [17]

We have to add the both half cell equations and eliminate the number of electrons lost/gained.

<h3>What modification must Kim make to the equations?</h3>

The term redox reaction is a type of reaction that occurs when an electron is lost or gained in a reaction system. We can see that in this reaction, zinc looses two electron which are gained by copper.

If we want to obtain the equation 4.9 which is the overall equation of the redox reaction from the various half cell equations then we have to add the both half cell equations and eliminate the number of electrons lost/gained.

Learn kore about redox reaction:brainly.com/question/13293425

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1 year ago