The addition of 0.1M HCl and 0.1M NaOH both of equal amounts is considered to be a neutralization reaction. A neutralization reaction is basically a double replacement reaction participated by both an acid and a base. In this case, the NaOH is the base while the HCl is the acid. The reaction will yield the following products: Water (H20) and aqueous Sodium Chloride (NaCl). Neutralization reactions always yield a salt and water as the end products.
Answer:
Kc = 1.4752
Explanation:
- CH4 (g) + 2H2O (g) ↔ CO2 (g) + 4H2 (g)
⇒ Kc = ( [ CO2(g) ] * [ H2 ]∧4 ) / ( [ CH4 ] * [ H2O ]² )
∴ [ CO2 ] = ( 8.01 g * ( mol / 44.01 g ) ) / 1.5 L
⇒ [ CO2 ] = 0.1213 M
⇒ [ H2O ] = 0.877 mol / 1.5 L = 0.585 M
⇒ [ CH4 ] = 0.380 mol / 1.5 L = 0.253 M
⇒ [ H2 ] = (( 0.380 mol CH4 ) * ( 4 mol H2 / mol CH4 )) / 1.5 L = 1.013 M
⇒ Kc = (( 0.1213 ) * ( 1.013 )∧4 ) / (( 0.253 ) * ( 0.585 )² )
⇒ Kc = 1.4752