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faust18 [17]
3 years ago
15

Where would an element be placed on the periodic table if it had a mass number of 304 amu, very low ionization energy, bonds eas

ily with other elements, melting point of 50.1 degrees Celsius, has the smallest electronegativity, predicatively the largest atomic radius, great metallic character, and silver in color
Chemistry
1 answer:
Natali5045456 [20]3 years ago
8 0

Answer:

  • As the atomic number is half of the atomic mass then it probably have 304/2 = 152 atomic number that will be placed before atom having atomic number 153 and after atom that have 151 atomic number.
  • According to all its properties it will be somewhere in the left or middle of the periodic table and will be at the bottom.
  • At the bottom in the super actinide metals series.

Explanation:

Data Given:

Predict place of element in the periodic Table having following properties

mass number = 304 amu

Ionization energy = very low

bonds = easily bond with other elements

melting point = 50.1° C

electronegativity = smallest    

Atomic radius = largest

metallic character = great

color =  silver  

Periodic Table is the table where elements were placed based on their atomic number.

In 1913 Mosley construct the periodic table according to their atomic number.

Modern Periodic Law :

the physical and chemical Properties of the elements are the periodic functions of their atomic number.

Atomic Number:

Atomic number is the number of electron or proton, denoted by Z

                Z = e or P

Atomic Mass:

Atomic mass is the number of proton plus neutron in the nucleus. it is denoted by A.

              A = P + N

Atomic number is almost half of the atomic mass for majority of the element.

Periodicity of periodic Table:

properties of the element repeat itself at certain interval.

Periodicity of Properties is as follow

1. Ionization energy:

The Ionization energy increase from left to right and decreases down the group.

2. Electronegativity:

E.N increase from left to right and decreases down the group.

3. metallic character:

Metallic character increase down the group and decrease from left to right. metals have metallic color, bristle and shiny surface.

4. non-metallic character

Non-metallic character decreases down the group and increases from left to right.

5. Melting point and boiling Point:

Melting point and boiling Point increases when the metallic character increase and decreases when the metallic character decreases.

6. Atomic radius :

Atomic Radius decrease from left to right and increases from top to bottom as shells are added.

Now keeping in mind all above points, to predict the place of the atom whose properties are given.

  • As the atomic number is half of the atomic mass then it probably have 304/2 = 152 atomic number that will be placed before atom having atomic number 153 and after atom that have 151 atomic number.
  • According to all its properties it will be somewhere in the left or middle of the periodic table and will be at the bottom.
  • At the bottom in the super actinide metals series.
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When heated a sample consisting of only CaCO3 and MgCO3 yields a mixture of CaO and Mgo. If the weight of the combined oxides is
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Answer:

38.83 %  of  CaCO3

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Explanation:

where Moles of CaCO3 is equals to x and MgCO3 is y we have that...

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MgCO3 molar mass = 84.31 g / mol  = 84.31 y

decomposition reactions :

CaCO3 ---> CaO + CO2

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So we have that , Moles of CaO = Moles of CaCO3 = x

and Moles of MgO = Moles of MgCO3 = y

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56.08 x + 40.30 y = 0.51 ( 100.09 x + 84.31 y )

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y = 1.87 x    

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= 100.09 x × 100 / ( 100.09 x + 84.31 y )

= 10009 x / ( 100.09 x + 84.31 × 1.87 x )

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= 10009 / 257.75

= 38.83 %

MgCO3 % in the sample

= 100 - 38.83  

=   61.17 %  

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