Answer:
m = 0.3249 g
Explanation:
First, I'm assuming you have a reaction of mercury(II) oxyde descomposition. If this is the case, then the equation to use is the following:
HgO ---------> Hg + O2
Balancing the equation:
2HgO ----------> 2Hg + O2
This means that 2 moles of HgO reacts to produce 1 mole of O2, so, we first calculate the moles of O2, then, the moles of HgO and finally the mass:
We have the volume of O2, the pressure and temperature, so let's use the ideal gas equation:
PV = nRT
Solving for n:
n = PV/RT
R: 0.082 L atm / K mole
T = 70 + 273 = 343 K
V = 83 / 1000 = 0.083 L
Calculating n:
n = 1 * 0.083 / 0.082 * 343
n = 0.003 moles
as stated before, 2 moles of HgO reacts with 1 mole of oxygen so:
2 moles HgO = 1 moles O2
moles HgO = moles O2 / 2
moles HgO = 0.003 / 2 = 0.0015 moles
Finally, to calculate the mass:
m = n * MM
the molar mass of HgO is 216.59 g/mol, so replacing:
m = 0.0015 * 216.59
m = 0.3249 g
Answer:
NBr3 has a trigonal pyramidal geometry where the nitrogen atom is bonded to three bromine atoms and has one lone pairs. The individual bonds are polar, as bromine is less electronegative than nitrogen. The overall compound is also polar, as the dipoles do not cancel.
Explanation:
Answer:
The correct answer is 1.89130 × 10⁻² g per ml.
Explanation:
Based on the given information, the volume of the water sample is 46 ml, the temperature given is 21 degree C. Weight of the compound mineral X is 0.87 grams obtained post evaporating, washing, and drying of the sample. Yes, on the basis of the given information, one can find the solubility of compound X in water at 21 degree C.
As 46 ml of water comprise 0.87 grams of the mineral compound X. Therefore, 1 ml of the water sample will comprise,
= 0.87/46 g of X
= 1.89130 × 10⁻² grams
Hence, the solubility of the compound X in the sample of water is 1.89130 × 10⁻² gram per ml.
Answer:
The new pressure of a gas initially at 575 mmhg and 12500ml and the volume changed to 15L is 479. 16 mmHg
Explanation:
Boyle's law states that the pressure of a given quantity of gas varies inversely with its volumes at constant temperature. It is represented as;
P V = K
P1 V1 = P2 V2
Where;
P1 = Initial pressure = 575 mmHg
P2 = Final pressure?
V1 = Initial volume = 12500ml = 12500÷ 1000 = 12.5 Liters
V2 = Final pressure = 15 Liters
Calculations :
P2 = P1 V1 ÷ V2
P2 = 575 × 12.5 ÷ 15
P2 = 7187 . 5 ÷ 15
P2 = 479. 16 mmHg
Therefore, the new pressure is 479. 16 mmHg
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