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3 years ago

Can light bend around corners to reach an object

Chemistry

2 answers:

Sholpan [36]3 years ago

7 0

Answer: Yes, light can bend around corners. In fact, light always bends around corners to some extent.

Explanation:This is a basic property of light and all other waves. ... The ability of light to bend around corners is also known as "diffraction".

CaHeK987 [17]3 years ago

5 0

Yes, it can bend around corners

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vladimir1956 [14]

When it comes to physical changes like phase changes, there are two types of heat energy: sensible heat and latent heat. Sensible heat is the heat absorbed/released when you heat the substance but it doesn't change phase. An example would be heating lukewarm water. The substance is liquid all throughout. Latent heat, on the other hand, is the heat absorbed/released when there is a phase change. An example would be boiling water, because it changes liquid to vapor.

Hence, for freezing liquid, you use the latent heat, specifically the heat of fusion. The answer should be

2.5 g * (1 mol/18.02 g) * 6.03 kJ/mol = 0.84 kJ/mol

The answer is not in the choices. You only use Hvap if you boil water.

5 0

4 years ago

A compound has a molar mass of 90. grams per mole and the empirical formula CH2O. What is the molecular formula of this compound

Elanso [62]

The molecular formula of this compound is C3H603 XD

8 0

3 years ago

The equation for the reaction between copper and nitric acid is vCu + wHNO3--->xCu(NO3)2 + yNO + zH2O Balance the equation an

lana [24]

Answer:

The coefficients of the balanced equation are:

v= 1
w= 4
x= 1
y= 2
z=2

Explanation:

The Law of Conservation of Matter, also called the Law of Conservation of Mass or the Lomonósov-Lavoisier Law, postulates that "mass is neither created nor destroyed, it is only transformed". This means that the reagents interact with each other and form new products with different physical and chemical properties than the reagents, but the amount of matter or mass before and after a transformation (chemical reaction) is always the same. In other words, then the mass before the chemical reaction is equal to the mass after the reaction.

Then, you must balance the following chemical equation:

v Cu + w HNO₃ → x Cu(NO₃)₂ + y NO + z H₂O

For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts

Left side: 1 copper, 1 hydrogen, 1 nitrogen and 3 oxygen.
Right side: 1 copper, 2 hydrogen, 3 nitrogen and 8 oxygen.

The coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.

By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.

Generally, hydrogen and oxygen balance in the end. So you balance nitrogen first, because copper is already balanced (there is the same amount on both sides of the reaction). If w = 2, then:

Left side: 1 copper, 2 hydrogen, 2 nitrogen and 6 oxygen.
Right side: 1 copper, 2 hydrogen, 3 nitrogen and 8 oxygen.

But you see then that the oxygen is unbalanced and you have less quantity in the reagents. Then w must be greater. Being w = 4:

Left side: 1 copper, 4 hydrogen, 4 nitrogen and 10 oxygen.
Right side: 1 copper, 2 hydrogen, 3 nitrogen and 8 oxygen.

Going back to the idea of balancing nitrogen, being y = 2:

Left side: 1 copper, 4 hydrogen, 4 nitrogen and 10 oxygen.
Right side: 1 copper, 2 hydrogen, 4 nitrogen and 9 oxygen.

Balancing the hydrogen, being z = 2:

Left side: 1 copper, 4 hydrogen, 4 nitrogen and 10 oxygen.
Right side: 1 copper, 4 hydrogen, 4 nitrogen and 10 oxygen.

Since you have the same amount of each element on each side of the reaction, the reaction is balanced. Then, the balanced equation is:

Cu + 4 HNO₃ → Cu(NO₃)₂ + 2 NO + 2 H₂O

Finally:

v= 1
w= 4
x= 1
y= 2
z=2

6 0

3 years ago

The amount of water (density 1.00 g mL-1) in grams that must be added to 26.2 g of

Damm [24]

Answer:

1720.8g water are necessaries

Explanation:

Mass percent is defined as the mass of solute (In this case, MgCl2) in 100g of solution (Mass MgCl2 + Mass water). To solve this question we must find the mass of solution that we need to produce th 1.5% by mass solution. Thus, we can find the mass of water that we need as follows:

Mass solution:

26.2g MgCl2 * (100g Solution / 1.5g MgCl2) = 1747g solution

Mass water:

1747g solution - 26.2g MgCl2 = 1720.8g water are necessaries

5 0

3 years ago

A 3.53g sample of (NH4NO3) was added to 80.0mlof water in a constant pressure calorimeter of negligible heat capacity. As a resu

raketka [301]

Mass of water = 80 x 18
= 1440 grams

Specific heat of water = 4.186 J/gK

Heat absorbed from water = mCpΔT
= 1440 x 4.186 x (21.6 - 18.1)
= 21.1 kJ

Moles of NH₄NO₃ = 3.53 / (14 + 4 + 14 + 16 x 3)
= 0.044 mol

Heat of solution = 21.1/0.044 kJ/mol
= 480 kJ/mol

7 0

3 years ago