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maksim [4K]
3 years ago
13

Which is NOT part of a normal microscope? a.ocular b. nosepiece c.stage d.objective

Chemistry
2 answers:
kozerog [31]3 years ago
6 0

Answer:

Nose piece

Explanation:

I have never seen one on a normal microscope

Evgesh-ka [11]3 years ago
3 0

Answer:

I believe it is a Nose piece

Explanation:

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According to valence bond theory, which orbitals overlap in the formation of the bond in HCl?
SIZIF [17.4K]
A) 1s on H and 3p on Cl

In HCl, the H atom has only one valance electron. Each share an electron an therefore a single covalent bond is formed between the two. The bond in HCl is therefore a result of an overlap between 1s orbital and ONLY ONE of the lobes of the 3p orbital of Chlorine.
5 0
3 years ago
What is the molecular formula of a compound with an empirical formula P2O5 and a gram-molecular mass of 284 grams? And why?
Lana71 [14]
I really don’t know but

Phosphorus pentoxide is a white solid which does not have any distinct odour. The chemical formula of this compound is P4O10. However, it is named after its empirical formula, which is P2O5. The molar mass of phosphorus pentoxide corresponds to 283.9 g/mol.
5 0
2 years ago
Q: A 25.5 mL aliquot of HCl (aq) of unknown concentration was titrated with 0.113 M NaOH (aq). It took 51.2 mL of the base to re
blondinia [14]
M ( HCl ) = ?

V ( HCl ) = 25.5 mL in liters : 25.5 / 1000 => 0.0255 L

M ( NaOH ) = 0.113 M

V ( NaOH ) = 51.2 mL / 1000 => 0.0512 L

number of moles NaOH:

n = M x V

n = 0.113 x <span> 0.0512 => 0.0057856 moles of NaOH

mole ratio:

</span><span>HCl + NaOH = NaCl + H2O
</span><span>
1 mole HCl -------------- 1 mole NaOH
( moles HCl ) ----------- </span><span> 0.0057856 moles NaOH
</span>
(moles HCl ) = <span> 0.0057856 x 1 / 1
</span>
= <span> 0.0057856 moles of HCl
</span>
M ( HCl ) = n / V

M =  0.0057856 / <span>0.0255
</span>
= 0.227 M

Answer A

hope this helps!

4 0
3 years ago
Read 2 more answers
The heat of vaporization of water at 100°c is 40.66 kj/mol. Calculate the quantity of heat that is absorbed/released when 9.00 g
timofeeve [1]

Answer:

20.3 kJ of heat is absorbed when 9.00 g of steam condenses to liquid water.

Explanation:

Heat is being consumed during vaporization and heat is being released during condensation.

To vaporize 1 mol of water, 40.66 kJ of heat is being consumed.

Molar mass of water = 18.02 g/mol

Hence, to vaporize 18.02 g of water , 40.66 kJ of heat is being consumed.

So, to vaporize 9.00 g of water, (\frac{40.66}{18.02}\times 9.00)kJ of heat or 20.3 kJ of heat is being consumed

As condensation is a reverse process of vaporization therefore 20.3 kJ of heat is absorbed when 9.00 g of steam condenses to liquid water.

5 0
3 years ago
What are examples of smaller bodies ​
Inga [223]

comets, astroids oort clouds which surround the kuiper belt

8 0
3 years ago
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