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maksim [4K]
3 years ago
13

Which is NOT part of a normal microscope? a.ocular b. nosepiece c.stage d.objective

Chemistry
2 answers:
kozerog [31]3 years ago
6 0

Answer:

Nose piece

Explanation:

I have never seen one on a normal microscope

Evgesh-ka [11]3 years ago
3 0

Answer:

I believe it is a Nose piece

Explanation:

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Car manufacturers use radiation for which task?
Lilit [14]

ANSWER: B) drying paint

EXPLANATION: Car manufacturers use UV radiation to dry the paint o the vehicle. The high reflectivity of infrared radiation helps to keep the car interior cool. It also gives advantages over convection heating. It can provide both high intensity and low intensity heat and is a low cost heat source when compared in dollars per unit of energy consumed. The IR heating also doesn't penetrate deeply and apply heating only on the outer surface.

4 0
4 years ago
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The volume of a gas is 50.0mL at 20.0K. What will be the new temperature if the gas is compressed to 10.0mL under constant press
mr Goodwill [35]

Answer:

4.0k

Explanation:

4 0
3 years ago
Why boiling point is less at hilly station?
pickupchik [31]
The atmospheric pressure at high altitudes like hill station is less than at the sea level. Thus, vapour pressure will equal atmospheric pressure at a comparatively low temperature. Thus, the boiling point of water is reduced less than at sea level.

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8 0
4 years ago
The correct lewis structure for COH2 contains how many covalent bonds?
VARVARA [1.3K]

Answer:

Four covalent bonds.

Explanation:

Hello,

In this case, given the attached picture in which you can find the Lewis dot structure for metanal (formaldehyde) we can see two C-H bonds and two C-O bonds via a double bond, thus, we can compute the type of each bond given the electronegativities of hydrogen, carbon and oxygen which are 2.1, 2.5 and 3.5 respectively:

C-H=2.5-2.1=0.4\\C-O=3.5-2.5=1.0

Thus, since both electronegativity difference are less 1.7 we infer that all of them are covalent, therefore, it has four covalent bonds, two C-H bonds and a double C-O bond.

Best regards-

8 0
4 years ago
Calculate the total amount of energy required in calories to convert 50.0 g of ice at 0.00 degrees Celsius to steam at 100. degr
GREYUIT [131]

<u>Answer: </u>The amount of heat absorbed is 36.0\times 10^3Cal

<u>Explanation:</u>

Few processes involved are:

(1): H_2O (s) (0^oC, 273K) \rightleftharpoons H_2O(l) (0^oC,273K)

(2): H_2O (l) (0^oC, 273K) \rightleftharpoons H_2O(l) (100^oC,373K)

(3): H_2O (l) (100^oC, 373K) \rightleftharpoons H_2O(g) (100^oC,373K)

Calculating the heat absorbed for the process having same temperature:

q=m\times \Delta H_{(f , v)} ......(i)

where,

q is the amount of heat absorbed, m is the mass of sample and is the enthalpy of fusion or vaporization

Calculating the heat released for the process having different temperature:

q=m\times C_{s,l}\times (T_2-T_1) ......(ii)

where,

C_{s,l} = specific heat of solid or liquid

T_2\text{ and }T_1 are final and initial temperatures respectively

  • <u>For process 1:</u>

We are given:

m=50.0g\\\Delta H_{fusion}=80Cal/g

Putting values in equation (i), we get:

q_1=50.0g\times 80Cal/g\\\\q_1=4000Cal

  • <u>For process 2:</u>

We are given:

m=50.0g\\C=1.00Cal/g^oC\\T_2=100^oC\\T_1=0^oC

Putting values in equation (i), we get:

q_2=50g\times 1Cal/g^oC\times (100-0)\\\\q_2=5000Cal

  • <u>For process 3:</u>

We are given:

m=50.0g\\\Delta H_{vap}=540Cal/g

Putting values in equation (i), we get:

q_3=50.0g\times 540J/g\\\\q_3=27000Cal

Calculating the total amount of heat released:

Q=q_1+q_2+q_3

Q=[(4000)+(5000)+(27000)]Cal=36000Cal=36.0\times 10^3Cal

Hence, the amount of heat absorbed is 36.0\times 10^3Cal

8 0
3 years ago
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