How many moles of H20 are produced from 6.4 moles of NaOH?

An empty erlenmeyer flask weighs 241.3 g. when filled with water (d = 1.00 g/cm3), the flask and its contents weigh 489.1 g. wha

g100num [7]

The volume of the flask would simply be equal to the volume of the water. And the mass of the water would be the difference after and before weigh.

mass of water = 489.1 g – 241.3 g

mass of water = 247.8 g

Therefore the volume of water (which is also the volume of the flask) is:

volume = 247.8 g / (1.00 g/cm^3)

volume = 247.8 cm^3

The total mass of the flash when filled with chloroform would be:

total mass with chloroform = 241.3 g + 247.8 cm^3 (1.48 g/cm3)

total mass with chloroform = 608.04 g

Answers:

volume = 247.8 cm^3

total mass with chloroform = 608.04 g

4 0

3 years ago

What is the mean free path for the molecules in an ideal gas when the pressure is 100 kPa and the temperature is 300 K given tha

sladkih [1.3K]

Answer:

The mean free path = 2.16*10^-6 m

Explanation:

Given:

Pressure of gas P = 100 kPa

Temperature T = 300 K

collision cross section, σ = 2.0*10^-20 m2

Boltzmann constant, k = 1.38*10^-23 J/K

To determine:

The mean free path, λ

Calculation:

The mean free path is related to the collision cross section by the following equation:

$\lambda =\frac{1}{n\sigma }------(1)$

where n = number density

$n = \frac{P}{kT}-----(2)$

Substituting for P, k and T in equation (2) gives:

$n = \frac{100,000 Pa}{1.38*10^{-23} J/K*300K} =2.42*10^{25}\ m^{3}$

Next, substituting for n and σ in equation (1) gives:

$\lambda =\frac{1}{2.42*10^{25}m^{-3}* .0*10^{-20}m^{2}}=2.1*10^{-6}m$

6 0

3 years ago

What volume of 18.0 m sulfuric acid is required to prepare 16.5 l of 0.126 m h2so4?

Blababa [14]

this is a dilution question where a certain volume is taken from a more concentrated solution and diluted to make a solution with a lower concentration.

the dilution forumla is as follows

c1v1 = c2v2

where c1 is concentration and v1 is volume of the more concetrated solution

c2 is concentration and v2 is volume of the diluted solution

substituting the values in the equation

18.0 M x V = 0.126 M x 16.5 L

V = 0.1155 L

volume of 115.5 mL is taken from the 18.0 M solution and diluted upto 16.5 L solution.

6 0

4 years ago

If 0.340 mol of a nonvolatile nonelectrolyte are dissolved in 3.10 mol of water, what is the vapor pressure PH2O of the resultin

SIZIF [17.4K]

Answer:

21.4 torr

Explanation:

The vapour pressure of a solution is lower than that of the pure solvent. And according to Raoult's law this depends of the amount of solute in the solvent. It is calculated according to the following equation

$P_{A} =X_{A} P^{o} _{A}$