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Romashka [77]
3 years ago
6

How does a heat affect the chemical reaction? ​

Chemistry
2 answers:
patriot [66]3 years ago
6 0

Answer:

Increasing the temperature increases reaction rates because of the disproportionately large increase in the number of high energy collisions. It is only these collisions (possessing at least the activation energy for the reaction) which result in a reaction.

Explanation:

vitfil [10]3 years ago
4 0
What the first one said
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Anna studies the color of her bedroom wall using different lights. In sunlight, she sees that the wall is white. Anna darkens th
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Answer: C white

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Which element has the ground state electron configuration 1s22s22p63s23p3?
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Its phosphorus (P)In writing the electron configuration for Phosphorus the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for Phosphorous go in the 2s orbital. The next six electrons will go in the 2p orbital. The p orbital can hold up to six electrons. We'll put six in the 2p orbital and then put the next two electrons in the 3s. Since the 3s if now full we'll move to the 3p where we'll place the remaining three electrons. Therefore the Phosphorus electron configuration will be 1s22s22p63s23p3.
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3 years ago
When a glow stick is crushed and shaken, the two liquids mix and the stick glows.
Mars2501 [29]

Answer:

A chemical change has occurred, with energy being given off.

Explanation:

The liquids mix and the stick gives off energy in light form

3 0
2 years ago
If 40.0 grams of zinc react with excess hydrochloric acid, how many grams of zinc chloride will be produced?
ludmilkaskok [199]

Answer:

Attached is the solution to the question

Explanation:

6 0
3 years ago
12oz of water initially at 75oF is mixed with 20oz of water intiially at 140oF. What is the final temperature?
Kaylis [27]

Answer:

115.625^{\circ}\text{F}

Explanation:

m_1 = First mass of water = 12 oz

m_2 = Second mass of water = 20 oz

\Delta T_1 = Temperature difference of the solution with respect to the first mass of water = (T-75)^{\circ}\text{F}

\Delta T_2 = Temperature difference of the solution with respect to the second mass of water = (T-75)^{\circ}\text{F}

c = Specific heat of water

As heat gain and loss in the system is equal we have

m_1c\Delta T_1=m_2c\Delta T_2\\\Rightarrow m_1\Delta T_1=m_2\Delta T_2\\\Rightarrow 12(T-75)=20(140-T)\\\Rightarrow 12T-900=2800-20T\\\Rightarrow 12T+20T=2800+900\\\Rightarrow 32T=3700\\\Rightarrow T=\dfrac{3700}{32}\\\Rightarrow T=115.625^{\circ}\text{F}

The final temperature of the solution is 115.625^{\circ}\text{F}.

3 0
2 years ago
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