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Illusion [34]
2 years ago
15

An empty aerosol-spray can at room temperature (20 degrees celcius) is thrown into an incinerator where the temperature reaches

625 degrees celcius. If the gas inside the empty container was initially at a pressure of 1 atm, what pressure did it reach inside the incinerator? Assume the gas was at constant volume and the can did not explode. Answer in units of atm.
Chemistry
1 answer:
disa [49]2 years ago
7 0

Answer: well there was still gas in the can

Explanation:  so by putting it in the incinerator the gas in the can got hotter and hotter etc.  and you got yourself your thermal reaction

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A 1.8 g sample of octane C8H18 was burned in a bomb calorimeter and the temperature of 100 g of water increased from 21.36 C to
melomori [17]

Answer:

HEAT OF COMBUSTION PER GRAM OF OCTANE IS 1723.08 J OR 1.72 KJ/G OF HEAT

HEAT OFF COMBUSTION PER MOLE OF OCTANE IS 196.4 KJ/ MOL OF HEAT

Explanation:

Mass of water = 100 g

Change in temperature = 28.78 °C - 21.36°C = 7.42 °C

Heat capcacity of water = 4.18 J/g°C

Mass of octane = 1.8 g

Molar mass of octane = C8H18 = (12 * 8 + 1 * 18) g/mol= 96 + 18 = 114 g/mol

First is to calculate the heat evolved when 100 g of water is used:

Heat = mass * specific heat capacity * change in temperature

Heat = 100 * 4.18 * 7.42

Heat = 3101.56 J

In other words, 3101.56 J of heat was evolved from the reaction of 1.8 g octane with water.

Heat of combustion of octane per gram:

1.8 g of octane produces 3101.56 J of heat

1 g of octane will produce ( 3101.56 * 1 / 1.8)

= 1723.08 J of heat

So, heat of combustion of octane per gram is 1723.08 J

Heat of combustion per mole:

1.8 g of octane produces 3101.56 J of heat

1 mole of octane will produce X J of heat

1 mole of octane = 114 g/ mol of octane

So we have:

1.8 g of octane = 3101.56 J

114 g of octane = (3101.56 * 114 / 1.8) J of heat

= 196 432.13 J

= 196. 4 kJ of heat

The heat of combustion of octane per mole is 196.4 kJ /mol.

Mass of water = 100 g

Change in temperature = 28.78 °C - 21.36°C = 7.42 °C

Heat capcacity of water = 4.18 J/g°C

Mass of octane = 1.8 g

Molar mass of octane = C8H18 = (12 * 8 + 1 * 18) g/mol= 96 + 18 = 114 g/mol

First is to calculate the heat evolved when 100 g of water is used:

Heat = mass * specific heat capacity * change in temperature

Heat = 100 * 4.18 * 7.42

Heat = 3101.56 J

8 0
2 years ago
Which of the following is considered an ignition source?
matrenka [14]
A.

Weldings sparks could start fire on wood.

Lightning can ignite a fire one a tall tree

Open flames can start another fire if made in contact especially with flammable substances
4 0
3 years ago
What is an example of a solid turning into another state of matter? ​
Rom4ik [11]

Answer:

Explanation:

Let me start with a simple one:

An ice cube ( solid ) changing into water ( a liquid )

Another example:

Dry ice ( solid ) submiling.

HOPE IT HELPES

4 0
3 years ago
What happens as a liquid freezes?
Sindrei [870]
The particles bunch together and can no longer move
8 0
3 years ago
Read 2 more answers
Plz help u might find it easy
PIT_PIT [208]

The melting point of pure lead : 327 °C

<h3>Further explanation</h3>

Given

Amount of tin and melting point of solder

Required

The melting point

Solution

The composition of solder = tin and lead

So if it is 100% tin, 0% lead or 0% tin, 100% lead

From the table it is shown that when the position is 100% tin in the solder, the melting point of the solder is 232 °C, so it shows that the melting point of pure lead is obtained when% tin in solder = 0 (100% lead in solder), so that the melting point is obtained. : 327 °C

3 0
2 years ago
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