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Gnoma [55]
3 years ago
6

Which phrase best describes the usual form and function of a flowers sepal

Physics
1 answer:
maw [93]3 years ago
8 0
D. Is leaf like and protects the developing flower.
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A child on a playground swing makes a complete to-and-fro swing each two seconds. the frequency of the swing is
Allisa [31]
0.5 swings per second (0.5 swings/sec if you want it shorter)
7 0
3 years ago
A fisherman notices that his boat is moving up and down periodically without any horizontal motion, owing to waves on the surfac
leva [86]

Answer:

A. 5.600 m

B. 5.800 s

C. 0.966 m/s

D. 0.315 m

Explanation:

A. The wavelength is the distance between 2 crests, which is 5.600 m

B. Period of the wave is the time for the wave to complete 1 circle (highest point to next highest point). Since it takes 2.9s to travel from highest point to lowest point, it would take another 2.9 to travel from lowest point to the next highest point. So the total time is 2.9 + 2.9 = 5.8 s,

C. The wavespeed is wavelength over unit of time:

5.6 / 5.8 = 0.966 m/s

D. The amplitude would be half the length of highest point to lowest point, which is 0.63 / 2 = 0.315 m

5 0
3 years ago
What is the acceleration of a proton moving with a speed of 7.0 m/s at right angles to a magnetic field of 1.7 t ?
Ivenika [448]
We know that a charge moving in a magnetic field is subject to the force:
F = q · v · B

But we also know that:
F = m · a

Therefore, it must be:
m · a = <span>q · v · B

And solving for a:
</span>a = <span>q · v · B / m

Recall that for a proton:
q = 1.6</span>×10⁻¹⁹ C
m = 1.673×10⁻²⁷ kg

Now, you can find:
a = 1.6×10⁻¹⁹ · 7.0 · 1.7 / <span>1.673×10⁻²⁷
   = 1.14</span>×10⁹ m/s²

Hence, the acceleration of the proton is 1.14<span>×10⁹ m/s²</span>.
8 0
3 years ago
By how much would 1500j of heat energy raise the temperature of 0.50kg of aluminum​
valentinak56 [21]

pls what is the specific heat capacity of water

7 0
3 years ago
A 50 gram meterstick is placed on a fulcrum at its 50 cm mark. A 20 gram mass is attached at the 12 cm mark. Where should a 40 g
alekssr [168]

Answer:

The 40g mass will be attached at 69 cm

Explanation:

First, make a sketch of the meterstick with the masses placed on it;

--------------------------------------------------------------------------

               ↓                    Δ                      ↓

             20 g.................50 cm.................40g

                         38 cm                  y cm  

Apply principle of moment;

sum of clockwise moment = sum of anticlockwise moment

40y = 20 (38)

40y = 760

y = 760 / 40

y = 19 cm

Therefore, the 40g mass will be attached at 50cm + 19cm = 69 cm

              12cm             50 cm              69cm

--------------------------------------------------------------------------

               ↓                    Δ                      ↓

             20 g.................50 cm.................40g

                         38 cm                 19 cm                                              

                                                                                                                                                                                                                                                                                                                                                                                                                                                                                   

5 0
3 years ago
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