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Alexxx [7]
3 years ago
9

If you know that the exact volume of a cylinder is 500 π cm3, how can you find the approximate volume, without knowing the heigh

t or radius of the cylinder? Answer in a full sentence, and then calculate the approximate volume
Mathematics
1 answer:
OLga [1]3 years ago
5 0
The formula for the volume of a cylinder ( V<span>=πr2</span>h) is useable to find the missing height. Then, to find the radius, use the equation, <span>r = square root of (V / (pi x h)). Plug your numbers into the equation and solve.</span>
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Find the equation of the line that contains the point (3,9) and is parallel to the line y=4x+1. Write the line in slope-intercep
Aleksandr-060686 [28]
Y = 4x + 1....slope here is 4. A parallel line will have the same slope

y = mx + b
slope(m) = 4
(3,9)...x = 3 and y = 9
now we sub and find b, the y int
9 = 4(3) + b
9 = 12 + b
9 - 12 = b
-3 = b

so ur parallel equation is : y = 4x - 3
5 0
3 years ago
The cost of fencing a square garden at the rate of Rs.5 per
Alex787 [66]

\huge\underline{\overline{\mid{\bold{\red{ANSWER}}\mid}}}

Cost per metre = Rs. 5

Total cost = Rs. 2000

Then total length of the fence = Rs.2000/Rs.5

= 400 metre

Total length of the fence = 400 metre

4 0
3 years ago
The measure of one of the acute angles in a right triangle is given. what is the measure of the other angle?
yuradex [85]
This is your favourite answer

5 0
2 years ago
A fruit bowl has 5 apples 7 oranges and 4 bananas. What is the ratio of apples to bananas?
Korolek [52]

Answer:

5 apples to 4 bananas

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces. A random sample of 15 co
Luda [366]

Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let \mu = <u><em>mean weight of coffee in its containers.</em></u>

SO, Null Hypothesis, H_0 : \mu \geq 32 ounces     {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, H_A : \mu < 32 ounces      {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

                             T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean weight = 31.8 ounces

             s = sample standard deviation = 0.48 ounces

             n = sample of containers = 15

So, <u><em>the test statistics</em></u>  =  \frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }  ~ t_1_4  

                                      =  -1.614

The value of t test statistics is -1.614.

<u>Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.</u>

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u><em>we fail to reject our null hypothesis</em></u>.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

8 0
3 years ago
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