60 = a * (-30)^2
a = 1/15
So y = (1/15)x^2
abc)
The derivative of this function is 2x/15. This is the slope of a tangent at that point.
If Linda lets go at some point along the parabola with coordinates (t, t^2 / 15), then she will travel along a line that was TANGENT to the parabola at that point.
Since that line has slope 2t/15, we can determine equation of line using point-slope formula:
y = m(x-x0) + y0
y = 2t/15 * (x - t) + (1/15)t^2
Plug in the x-coordinate "t" that was given for any point.
d)
We are looking for some x-coordinate "t" of a point on the parabola that holds the tangent line that passes through the dock at point (30, 30).
So, use our equation for a general tangent picked at point (t, t^2 / 15):
y = 2t/15 * (x - t) + (1/15)t^2
And plug in the condition that it must satisfy x=30, y=30.
30 = 2t/15 * (30 - t) + (1/15)t^2
t = 30 ± 2√15 = 8.79 or 51.21
The larger solution does in fact work for a tangent that passes through the dock, but it's not important for us because she would have to travel in reverse to get to the dock from that point.
So the only solution is she needs to let go x = 8.79 m east and y = 5.15 m north of the vertex.
10,800 would be the best awnser for you
Answer:
Solve for
K
by simplifying both sides of the equation, then isolati.ng the variable.
K
=
m
v
2 i.f yo.u wa.nt th.e re.al answ.er g.o h.ere: >>>>https://www.math.way.com/po.pular-prob.lems/Alg.ebra/229798
2
Step-by-step explanation:
Answer:
3 oz. Left
Step-by-step explanation:
First there are 16 oz in 1 pound
Multiply 4 by 16
Then divide 3÷4 and multiply that by 16
Your total should be 76
Subtract 76-73
Your answer is 3 oz left
18/6
18= the number of trucks
6= the number of hours
18/6= 3 trucks per hour
