Answer:
unless acted upon by an unbalanced force.
Explanation:
If a ball is rolling, it will continue to roll forever, unless it is acted upon by an unbalanced force. For example, the friction of the floor it's rolling on slows it down. The density of the air hitting it also slows it down.
Answer:
c
Explanation:
Increasing the length of string to which the bob is attached, increases the radius of the circle on which the bob moves; and therefore, the frequency, or number of back and forth swings in a set time frame, will be less.
Answer;
V = 14.7 m/s
Explanation and solution;
Vx = V cos theta
Vx = 16m/s × cos 28.08
Vx = 14.1 m/s
Vy = Vsin theta
Vy = 7.51m/s
t = d/Vx
t = 16.8m/ 14.1
t= 1.191 s
Now, find Vy at t= 1.191
Vy = Vy - gt
Vy = 7.51 - 9.81*1.191
Vy = - 4.18 m/s
V = sqrt (Vy^2 +Vx^2)
V= sqrt (4.18^2 + 14.1^2)
V= 14.7m/s
Answer:
a) True. There is dependence on the radius and moment of inertia, no data is given to calculate the moment of inertia
c) True. Information is missing to perform the calculation
Explanation:
Let's consider solving this exercise before seeing the final statements.
We use Newton's second law Rotational
τ = I α
T r = I α
T gR = I α
Alf = T R / I (1)
T = α I / R
Now let's use Newton's second law in the mass that descends
W- T = m a
a = (m g -T) / m
The two accelerations need related
a = R α
α = a / R
a = (m g - α I / R) / m
R α = g - α I /m R
α (R + I / mR) = g
α = g / R (1 + I / mR²)
We can see that the angular acceleration depends on the radius and the moments of inertia of the steering wheels, the mass is constant
Let's review the claims
a) True. There is dependence on the radius and moment of inertia, no data is given to calculate the moment of inertia
b) False. Missing data for calculation
c) True. Information is missing to perform the calculation
d) False. There is a dependency if the radius and moment of inertia increases angular acceleration decreases
Hello!
Recall the period of an orbit is how long it takes the satellite to make a complete orbit around the earth. Essentially, this is the same as 'time' in the distance = speed * time equation. For an orbit, we can define these quantities:
← The circumference of the orbit
speed = orbital speed, we will solve for this later
time = period
Therefore:
Where 'r' is the orbital radius of the satellite.
First, let's solve for 'v' assuming a uniform orbit using the equation:
G = Gravitational Constant (6.67 × 10⁻¹¹ Nm²/kg²)
m = mass of the earth (5.98 × 10²⁴ kg)
r = radius of orbit (1.276 × 10⁷ m)
Plug in the givens:
Now, we can solve for the period: