Answer:
3.99*10^-3N/C
Explanation:
Using
Ep= kq/r²
Where r = 0.6mm = 0.6*10^-3m
K= 8.9*10^9 and q= 1.6*10^-19
So = 8.9*10^9 * 1.6*10^-19/0.6*10^-3)²
= 3.99*10^-3N/C
Answer:
Using equation 2dsinФ=n*λ
given d=2.41*10^-6m
λ=512*10^-12m
θ=52.64 degrees
Answer:
1.11 dioptre
Explanation:
= Distance of the image = - (125 - 2) = - 123 cm
= Distance of the object = 54 - 2 = 52 cm
= Focal length of the lens
Using the equation


cm
Power of the lens is given as


Dioptre
"Light year" is a distance, not a speed. It's the distance light travels in one year, at the speed of 299,792,458 meters per second.
Answer:
<h3>(A) The width

m</h3><h3>(B) The new width is

m</h3>
Explanation:
Given :
Focal length 
Maximum aperture
Wavelength
m
(A)
From rayleigh criterion,


rad
From angle formula,

Where
12 m ( given in example )
m

m
(B)
We know that
is proportional to the
and inversely proportional to the 
so we write the new width, here
is 5.5 times larger than above case

m