1 newton / square metre =0.0001 newton / square centimetre
Formula = divide the pressure value by 10000
A bicyclist can ride their bicycle still on the road. Bicycle riders be able to take the public ways which has the similar rights and accountability as motorists and are subject to the same guidelines and protocols. The law says that individuals who ride bikes should ride as nearby to the right side of the road as likely excluding under the following conditions: when passing, preparing for a left go, evading risks, if the lane is too constricted to share, or if oncoming a place where a right turn is approved. In a road which has a bike lane the bicyclists roving slower than road traffic must custom the bike way excluding when creating a left turn, passing, evading hazardous settings, or impending a place where a right turn is approved.
Answer:
a) 5 N b) 225 N c) 5 N
Explanation:
a) Per Coulomb's Law the repulsive force between 2 equal sign charges, is directly proportional to the product of the charges, and inversely proportional to the square of the distance between them, acting along the line that joins the charges, as follows:
F₁₂ = K Q₁ Q₂ / r₁₂²
So, if we make Q1 = Q1/5, the net effect will be to reduce the force in the same factor, i.e. F₁₂ = 25 N / 5 = 5 N
b) If we reduce the distance, from r, to r/3, as the factor is squared, the net effect will be to increase the force in a factor equal to 3² = 9.
So, we will have F₁₂ = 9. 25 N = 225 N
c) If we make Q2 = 5Q2, the force would be increased 5 times, but if at the same , we increase the distance 5 times, as the factor is squared, the net factor will be 5/25 = 1/5, so we will have:
F₁₂ = 25 N .1/5 = 5 N
Answer:
Part a)

Part B)

Part C)

Explanation:
Part A)
As we know that ball is hanging from the top and its angle with the vertical is 20 degree
so we will have






Part B)
Here we can use energy theorem to find the distance that it will move




Part C)
At terminal speed condition we know that




Answer:
109656.25 Nm
Explanation:
= Final angular velocity = 1.5 rad/s
= Initial angular velocity = 0
= Angular acceleration
t = Time taken = 6 s
m = Mass of disk = 29000 kg
r = Radius = 5.5 m

Torque is given by

The torque specifications must be 109656.25 Nm