1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dmitriy555 [2]
3 years ago
13

A generic element, G, is composed of two isotopes, 132G and 128G. 132G has a natural abundance of 90% and an isotopic mass of 13

1.90 amu, and 128G has a natural abundance of 10% and an isotopic mass of 127.90 amu. What is the average atomic mass of this element?
Chemistry
1 answer:
Sunny_sXe [5.5K]3 years ago
8 0

Answer: The average atomic mass of this element is 131.5 amu

Explanation:

Mass of isotope 1 = 131.90 amu

% abundance of isotope 1 = 90% = \frac{90}{100}=0.9

Mass of isotope 2 = 127.90 amu

% abundance of isotope 2 = 10% = \frac{10}{100}=0.1

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=\sum[(131.90\times 0.9)+(127.90\times 0.1)]=131.5amu

The average atomic mass of this element is 131.5 amu

You might be interested in
Astroturf is a durable artificial surface used to cover athletic fields. A soccer field 0.06214- mile-long by 253 ft wide is cov
love history [14]

Answer:

The weight of the Astroturf is 179,684.31 Newtons.

Explanation:

Length of a soccer field = 0.06214 mile = 328.0992 feet

(1 mile = 5280 feet)

Breadth of a soccer field  = 253 feet

Length of a Astroturf which soccer field is to be covered, l = 328.0992 feet

Breadth of a Astroturf which soccer field is to be covered ,b = 253 feet

Thickness of a Astroturf with which soccer field is to be covered = h

h = ½ inch = 0.5 inch = 0.041665 feet

(1 inches = 0.08333 feet)

Volume of the Astroturf ,V= l × b × h

V=328.0992 ft\times 253 ft\times 0.041665 ft=3,458.574 ft^3

Mass of the Astroturf = m

Density of the Astroturf = d = 187 oz/ft^3

d=\frac{m}{V}

m=d\times V= 187 oz/ft^3\times 3,458.574 ft^3=646,753.35 oz

1 oz = 0.0283495 kg

m=646,743.35 oz=646,743.35\times 0.0283495 kg=18,335.13 kg

Weight of the Astroturf = W

W = mg

=W=18,335.13 kg\times 9.8 m/s^2=179,684.31 N

The weight of the Astroturf is 179,684.31 Newtons.

8 0
3 years ago
A stream of surface water reaches a porous portion of sediment and seeps into the ground. This water eventually joins a large re
Fed [463]

The correct answer is - C. Hydrosphere; geosphere.

The hydrosphere is the sphere which contains all the waters on the planet Earth. The geosphere is the sphere that contains the solid rocky part of the Earth. When the water goes through the porous sediments and enters deeper into the ground, that means the we have an interaction of water and rocks. In other words, since the water is part of the hydrosphere, and the rocks are part of the geosphere, we have an interaction between the hydrosphere and the geosphere.

8 0
4 years ago
Read 2 more answers
How many grams are in 1.76 x 10^23 atoms of iodine
Mariana [72]

Answer:

\boxed {\boxed {\sf About \ 37.1 \ grams \ of \ iodine }}

Explanation:

To convert from atoms to grams, you must first convert atoms to moles, then moles to grams.

1. Convert Atoms to Moles

To convert atoms to grams, Avogadro's number must be used.

6.022*10^{23}

This number tells us the number of particles (atoms, molecules, ions, etc.) in 1 mole. In this case, the particles are atoms of iodine.

\frac{6.022*10^{23} \ atoms \ I  }{1 \ mol \ I}

Multiply the given number of atoms by Avogadro's number.

1.76*10^{23} \ atoms \ I*\frac{6.022*10^{23} \ atoms \ I  }{1 \ mol \ I}

Flip the fraction so the atoms of iodine will cancel out.

1.76*10^{23} \ atoms \ I*\frac{  1 \ mol \ I}{6.022*10^{23} \ atoms \ I}

1.76*10^{23}* \frac{1 \ mol \ I}{6.022*10^{23} }

Multiply so the problem condenses into 1 fraction.

\frac{1.76*10^{23} \ mol \ I}{6.022*10^{23} }

0.2922617071 \ mol \ I

2. Convert Moles to Grams

Now we must use the molar mass of iodine, which is found on the Periodic Table.

  • Iodine Molar Mass: 126.9045 g/mol

Use this mass as a fraction.

\frac{ 126.9045 \ g\ I }{ 1 \ mol \ I}

Multiply this fraction by the number of moles found above.

0.2922617071 \ mol \ I*\frac{ 126.9045 \ g\ I }{ 1 \ mol \ I}

Multiply. The moles of iodine will cancel.

0.2922617071 *\frac{ 126.9045 \ g\ I }{ 1 }

The 1 as a denominator is insignificant.

0.2922617071 *{ 126.9045 \ g\ I }

37.08932581 \ g \ I

3. Round

The original measurement of 1.76*10^23 has 3 significant figures (1, 7, and 6). Therefore we must round our answer to 3 sig figs. For this answer, that is the tenths place.

37.08932581 \ g \ I

The 8 in the hundredth place tells us to round the 0 up to a 1.

\approx 37.1\ g \ I

There is about <u>37.1 grams of iodine </u>in 1.76*10^23 atoms.

5 0
3 years ago
A pogo stick bounces 30 M in 10 secs what is the bouncers average speed?
DiKsa [7]
I would love to help but it is 3 or is it 3 million?
7 0
4 years ago
Read 2 more answers
Arjun placed a salt cube in a cup of water. He wonders whether stirring the water will make the salt cube
Ilya [14]

Explanation:

Yes...the molecules would get warmer has they collide into each Other...

8 0
3 years ago
Other questions:
  • A freight train rushed down the track going south at 60 mph. This is an example of ____.
    10·1 answer
  • How many protons does the largest transition metal have in its nucleus?
    10·2 answers
  • I am a subatomic particle <br> that is positively charged what am I?
    8·1 answer
  • NEEDS TO BE CORRECT EXPLAIN!!!!! I'M GIVING 50 POINTS!!!!!!!
    10·2 answers
  • PLEASE HURRY
    5·1 answer
  • Which element has the highest thermal conductivity
    7·1 answer
  • Answer as many as you can please, 40 POINTS
    5·1 answer
  • A___________ consists of a mixture of graphite powder (a form of carbon) and clay that is baked and hardened and encased in wood
    7·1 answer
  • 1. 2.0 mL/s x 4.0 hrs = ? L<br><br> How do you do this conversion problem
    5·1 answer
  • ____________ rays show areas where large quantities of energy are released.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!