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dmitriy555 [2]
3 years ago
13

A generic element, G, is composed of two isotopes, 132G and 128G. 132G has a natural abundance of 90% and an isotopic mass of 13

1.90 amu, and 128G has a natural abundance of 10% and an isotopic mass of 127.90 amu. What is the average atomic mass of this element?
Chemistry
1 answer:
Sunny_sXe [5.5K]3 years ago
8 0

Answer: The average atomic mass of this element is 131.5 amu

Explanation:

Mass of isotope 1 = 131.90 amu

% abundance of isotope 1 = 90% = \frac{90}{100}=0.9

Mass of isotope 2 = 127.90 amu

% abundance of isotope 2 = 10% = \frac{10}{100}=0.1

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=\sum[(131.90\times 0.9)+(127.90\times 0.1)]=131.5amu

The average atomic mass of this element is 131.5 amu

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erik [133]

Answer:

Option B. 4.74×10¯¹⁹ J.

Explanation:

The following data were obtained from the question:

Wavelength (λ) = 4.2×10¯⁷ m

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Next, we shall determine the frequency of the wave. This can be obtained as follow:

Wavelength (λ) = 4.2×10¯⁷ m

Velocity (v) = constant = 3×10⁸ m/s

Frequency (f) =.?

v = λf

3×10⁸ = 4.2×10¯⁷ × f

Divide both side by 4.2×10¯⁷

f = 3×10⁸ / 4.2×10¯⁷

f = 7.143×10¹⁴ s¯¹

Therefore, the frequency of the wave is 7.143×10¹⁴ s¯¹.

Finally, we shall determine the energy of the wave using the following formula

E = hf

Where

E is the energy.

h is the Planck's constant

f is the frequency

Thus, the enery of the wave can be obtained as follow:

Frequency (f) = 7.143×10¹⁴ s¯¹.

Planck's constant = 6.63×10¯³⁴ Js

Energy (E) =..?

E = hf

E = 6.63×10¯³⁴ × 7.14×10¹⁴

E = 4.74×10¯¹⁹ J

Therefore, the energy of the wave is 4.74×10¯¹⁹ J.

5 0
3 years ago
In the process of making soap, I poured some of the cooked mixture through some muslin fabric, in order to separate the solid pa
lyudmila [28]

Answer:

filtering

Explanation:

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6 0
3 years ago
2. Calculate the mass of K in 90g of KOH​
ValentinkaMS [17]

KOH = 90g

KOH = 57 g/mol

K = 40g/mol

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The mass of K is 63.15g

8 0
2 years ago
How many grams of water can I convert from a liquid to a gas with 6768 joules?
vredina [299]

Answer:

The amount of water converted from liquid to gas with 6,768 joules is approximately 3.035 g

Explanation:

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The latent heat of evaporation of water, ΔH_v ≈ 2,230 J/g

The relationship between the heat supplied, 'Q', and the amount of water in grams, 'm', evaporated is given as follows

Q = m × ΔH_v

Therefore, the amount of water, 'm', converted from liquid to gas at the boiling point temperature (100°C), when Q = 6,768 Joules, is given as follows;

6,768 J = m × 2,230 J/g

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The amount of water converted from liquid to gas with 6,768 joules = m ≈ 3.035 g.

8 0
3 years ago
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makvit [3.9K]

Answer:

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cathode: Cu²⁺  + 2e⁻    ⇒     Cu

anode:    Cu     ⇒       Cu²⁺  + 2e⁻

3 0
3 years ago
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