Answer: (1,1)
Step-by-step explanation:
<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
Answer:
(2A /h) - b1 = b2
Step-by-step explanation:
A = 1/2 h ( b1 + b2)
Multiply each side by 2
2A = 2*1/2 h ( b1 + b2)
2A = h ( b1 + b2)
Divide each side by h
2A/h= h/h ( b1 + b2)
2A/h= b1 + b2
Subtract b1 from each side
2A /h - b1 = b2
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