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Minchanka [31]
3 years ago
12

If the absolute temperature of a gas is 600 K, the temperature in degrees Celsius is: A. 705°C. B. 873°C. C. 273°C. D. 327°C

Physics
1 answer:
zlopas [31]3 years ago
4 0

Answer:

D). 327 ^0 C

Explanation:

As we know that temperature scale is linear so we will have

\frac{^0C - 0}{100 - 0} = \frac{K - 273}{373 - 273}

now we have

\frac{^0 C - 0}{100} = \frac{K - 273}{100}

so the relation between two scales is given as

^0 C = K - 273

now we know that in kelvin scale the absolute temperature is 600 K

so now we have

T = 600 - 273 = 327 ^0 C

so correct answer is

D). 327 ^0 C

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What are the four types of musical instruments and what are the physical behind each type of musical instrument
pishuonlain [190]

Answer:

The four types of musical instruments are percussion, woodwind, brass, and strings.

Explanation:

Percussion instruments include drums, triangle, cymbals, and xylophones. There are more instruments than what i've mentioned though. Percussion instruments often produce the beat of songs.

Woodwind instruments include clarinets, oboe, flute, and saxophone. Woodwind instruments often produce the harmony of songs and, occasionally, the melody.

Brass instruments include trumpet, trombone, french horn, and tuba. Brass instruments often produce the harmony of songs, the trumpet produces the melody a lot though.

String instruments include guitars, violins, cello, bass, ukulele, and banjo. String instruments produce both the harmony and the melody. These instruments often produce really beautiful music, in my opinion.

8 0
3 years ago
Milk containing 3.7% fat and 12.8% total solids is to be evaporated to produce a product containing 7.9% fat. What is the yield
ratelena [41]

Answer:

the yield of product is YP=46.835 % and the concentration of solids is

Cs = 27.33%

Explanation:

Assuming that all the solids and fats remains in the milk after the evaporation, then the mass of product mP will be

Mass of fat in 100 kg of milk = 100 kg* 0.037 = mP* 0.079

mP = 100 kg* 0.037/0.079  =  46.835 kg

then the yield YP of the product is

YP= mP / 100 kg =  46.835 kg / 100 kg = 46.835 %

YP= 46.835 %

the concentration of solids Cs is

Mass of solids in 100 kg of milk = 100 kg* 0.128 = 46.835 kg * Cs

Cs = 100 kg* 0.128 / 46.835 kg  = 0.2733 = 27.33%

Cs = 27.33%

3 0
3 years ago
If 745-nm and 660-nm light passes through two slits 0.54 mm apart, how far apart are the second-order fringes for these two wave
kotegsom [21]

Answer:

0.82 mm

Explanation:

The formula for calculation an n^{th} bright fringe from the central maxima is given as:

y_n=\frac{n \lambda D}{d}

so for the distance of the second-order fringe when wavelength \lambda_1 = 745-nm can be calculated as:

y_2 = \frac{n \lambda_1 D}{d}

where;

n = 2

\lambda_1 = 745-nm

D = 1.0 m

d = 0.54 mm

substituting the parameters in the above equation; we have:

y_2 = \frac{2(745nm*\frac{10^{-9m}}{1.0nm}(1.0m) }{0.54 (\frac{10^{-3m}} {1.0mm})}

y_2 = 0.00276 m

y_2 = 2.76 × 10 ⁻³ m

The distance of the second order fringe when the wavelength \lambda_2 = 660-nm is as follows:

y^'}_2 = \frac{2(660nm*\frac{10^{-9m}}{1.0nm}(1.0m) }{0.54 (\frac{10^{-3m}} {1.0mm})}

y^'}_2 = 1.94 × 10 ⁻³ m

So, the distance apart the two fringe can now be calculated as:

\delta y = y_2-y^{'}_2

\delta y = 2.76 × 10 ⁻³ m - 1.94 × 10 ⁻³ m

\delta y = 10 ⁻³ (2.76 - 1.94)

\delta y = 10 ⁻³ (0.82)

\delta y = 0.82 × 10 ⁻³ m

\delta y =  0.82 × 10 ⁻³ m (\frac{1.0mm}{10^{-3}m} )

\delta y = 0.82 mm

Thus, the distance apart the second-order fringes for these two wavelengths = 0.82 mm

6 0
3 years ago
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sineoko [7]

Answer:

When work is being done, the practie of labor is being performed. When work isn't being completed, this is a sign of procrastination.

Explanation:

In the answer.

5 0
3 years ago
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natta225 [31]

Answer:

Cabinets are made to open one at a time so that there's not much of space taken up when all the drawers are open. Hope this helps.

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