<span>he ratio of the RMS velocities is 0.837
Now the RMS velocity is inversely proportional to the square root of the Mol Wt
So we have V1/V(N2) = sq rt (28/M1)
So [V1/V(N2)]^2 = 0.837^2 = 0.70 = 28/M1 from which M1 = 28/0.7 = 39.97 (Ar)</span>
KE = (1/2)mv^2
m = 10.0 kg
v = 5.00 m/a
KE = (1/2)(10.0)(5.00)^2 = (1/2)(10.0)(25.0) = 125 J
C. 125 J
The original results have not been replicated consistently and reliably.
Answer:
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