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nlexa [21]
3 years ago
12

The uniform circular motion of a space station can be used to create artificial gravity. This can be done by adjusting the angul

ar speed of the space station, so the centripetal acceleration at an astronaut's feet equals g, the magnitude of the acceleration due to the earth's gravity. If such an adjustment is made, what will be true about the acceleration at the astronaut's head due to the artificial gravity?
Physics
1 answer:
DENIUS [597]3 years ago
3 0

Answer:

The acceleration at the astronaut's head decreases.

Explanation:

Since the centripetal acceleration equals acceleration due to gravity,

a = g = GM/R². since a changes infinitesimally from his foot to his head, we differentiate a with respect to r to get da/dr = -2GM/R³.

So, da, the change in acceleration = -2GMdR/R³ = -2gdR/R = -2 × 9.8/6.4 × 10⁶ m =  -3.0625 × 10⁻⁶dR m/s².

Since dR = height of astronaut = 1.80 m, da = -3.0625 × 10⁻⁶ × 1.8 = -5.5125 × 10⁻⁶ m/s².

So the acceleration at the astronaut's head is g + da = 9.8 - 0.0000055125 = 9.7999944875 m/s².

So the acceleration at the astronaut's head decreases.

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Explanation:

Step 1:

Speed of sound in water varies from 1450 to 1498 meters per second

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Speed of sound in cold air is approximately 293.33 meters per second

Step 2:

In warm air sound travels faster than that of sound travelling nature in cold air.

∴ Speed of sound in cold air < Speed of sound in Warm air < Speed of sound in hot molten lead < Speed of sound in water

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The slope of the following graph represents
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What is the smallest radius of an unbanked (flat) track around which a bicyclist can travel if her speed is 22 km/h and the coef
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F_{fric}= mg \mu_{s}

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