Answer:
The final temperature of the mixture is 21.4°C
Explanation:
Specific heat capacity of water = 1 cal/g°c
Heat loss by water = 77.1 g X 1 cal/g°c X 50.9°c = 3924.39 Cal
Latent heat of fusion of ice = 79.7 g⁻¹
Heat required to melt ice at 0°c= 22.5 g X 79.7 g⁻¹ = 1793.25 Cal
Heat gained by ice from water at a higher temperature, T°c = 22.5 X 1 X T
= 22.5T
Also heat lost by water = 77.1 X 1 X (50.9-T)cal
By calorimetric principle
Heat lost by a hot body = heat gained by a cold body
77.1 X 1 X (50.9-T) = 22.5T + 1793.25
3924.39 -77.1T = 22.5T + 1793.25
99.6T = 3924.39 - 1793.25
T = 2131.14/99.6
T = 21.4°C
Therefore, the final temperature of the mixture is 21.4°C
Answer: As the atomic radii increases, the ionization energy decreases.
Explanation: Atomic Radii is the distance between the centre of the nucleus/atom and the outermost shell, while the ionization energy is the minimum energy required to remove the most loosely bound electron/valence electron from an isolated neutral gaseous atom/molecule.
As the number of shells increases, the atomic radius of an atom logically increases, and the force of attraction between the relatively positively charged heavy nucleus (positively charged because it contains protons and heavy because the protons & neutrons have great masses relative to the mass of an electron) and the electrons on the outermost shell reduces because of the increasing distance between this two entities. The reduction in the forces of attraction, makes it easier to remove that valence electron on the outermost shell as the size increases. This is why the ionization energy decreases with increase in atomic radius thereby leading to a decrease in ionization energy as we move down the group (of a periodic table).
Across the period (left to right), elements in the same period have the same number of shells, but the electrons in the outermost shell increases as we go from left to right, leading to a tighter hold on the increasing electrons by the nucleus. This is why atomic radius decreases & ionization energy consequently increase across a period.
More energy is required to remove the valence electrons as the force of attraction between nucleus & valence electrons on the outermost shell increases.
Answer:
The prime difference lies in the fact that pure substances cannot be physically separated while mixtures can be. The separation of a mixture into its different parts is done by using physical techniques like distillation, filtering and particle separation.
Answer:
The coefficients are: 1, 2, 1, 2
Explanation:
To know which option is correct, we shall balance the equation. This can be obtained as follow:
SnO₂ + H₂ —> Sn + H₂O
There are 2 atoms of O on the left side and 1 atom on the right side. It can be balance by writing 2 before H₂O as shown below:
SnO₂ + H₂ —> Sn + 2H₂O
There are 2 atoms of H on the left side and a total of 4 atoms on the right side. It can be balance by writing 2 before H₂ as shown below:
SnO₂ + 2H₂ —> Sn + 2H₂O
Now the equation is balanced.
The coefficients are: 1, 2, 1, 2
Thus, none of the options are correct.
Answer:
The weight/weight % or percent by mass of the solute is 1.04g.mL
Explanation:
We assume, (i) that the solvent is water, and (ii) that dissolution occurs without change in volume.
So given the standard density of water, the mass of the solution is simply,
(4.87+86.4)g
For solution,
=
= 1.04 g. mL
Because nitrate salts are soluble stuff, you could get significantly higher solution densities if you dissolved more salt (volume change would be fairly negligible).