Use formula: Initial Pressure x Initial Volume/Initial temperature = Final pressure x Final Volume/Final Temperature => 17.15L
<h3>
Answer:</h3>
0.6 g NaCl
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN - Balanced] Na₂CO₃ (aq) + CaCl₂ (aq) → CaCO₃ (s) + 2NaCl (aq)
[Given] 0.5 g Na₂CO₃ reacted with excess CaCl₂
<u>Step 2: Identify Conversions</u>
[RxN] Na₂CO₃ → 2NaCl
Molar Mass of Na - 22.99 g/mol
Molar Mass of C - 12.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of Cl - 35.45 g/mol
Molar Mass of Na₂CO₃ - 2(22.99) + 12.01 + 3(16.00) = 105.99 g/mol
Molar Mass of NaCl - 22.99 + 35.45 = 58.44 g/mol
<u>Step 3: Stoichiometry</u>
- Set up:

- Multiply/Divide:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 1 sig fig.</em>
0.551373 g NaCl ≈ 0.6 g NaCl
Answer: a) 
b) 
Explanation:
The reaction is :

Rate = Rate of disappearance of
= Rate of appearance of
Rate =
= ![\frac{d[NO_2]}{4dt}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BNO_2%5D%7D%7B4dt%7D)
Rate of disappearance of
=
= 
a) Rate of disappearance of
= ![-\frac{d[N_2O_5]}{2dt}](https://tex.z-dn.net/?f=-%5Cfrac%7Bd%5BN_2O_5%5D%7D%7B2dt%7D)
Rate of appearance of
= ![\frac{d[NO_2]}{4dt}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BNO_2%5D%7D%7B4dt%7D)
b) Rate of appearance of
= ![\frac{d[NO_2]}{dt}=2\times 1.7\times 10^{-4}}=3.4\times 10^{-4}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BNO_2%5D%7D%7Bdt%7D%3D2%5Ctimes%201.7%5Ctimes%2010%5E%7B-4%7D%7D%3D3.4%5Ctimes%2010%5E%7B-4%7D)
Analytical
Analytical chemistry seeks to determine the composition of substances.