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2 years ago

How much ice at 0°C could be melted by the addition of 15 kJ of heat? (ΔHfus = 6.01 kJ/mol)

Chemistry

2 answers:

BARSIC [14]2 years ago

7 0

Answer:

d. 45 g

Explanation:

The amount of ice melted is:

$\Delta n = \frac{15\,kJ}{6.01\,\frac{kJ}{mol} }$

$\Delta n = 2.496\,moles$

$\Delta m = \Delta n \cdot M_w$

$\Delta m = (2.496\,moles)\cdot \left(18\,\frac{g}{mol} \right)$

$\Delta m = 44.928\,g$

anzhelika [568]2 years ago

5 0

Answer: d.45 g

Explanation:see attached photo

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The light traveled from _____________________ to __________________. (What transparent materials?)

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Explanation:

High density medium to low density medium.

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2 years ago

Is a pH of 7 high pH or neutral??

navik [9.2K]

Answer:

neutral

Explanation:

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3 years ago

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A gas is collected at 30 Celsius and has a pressure of 200 kPa. What pressure would it exert if the temperature changed to 40 Ce

garik1379 [7]

Answer:

$206.6\ \text{kPa}$

Explanation:

$P_1$ = Initial pressure = 200 kPa

$P_2$ = Final pressure

$T_1$ = Initial temperature = $30^{\circ}\text{C}$

$T_2$ = Final temperature = $40^{\circ}\text{C}$

We have the relation

$\dfrac{P_2}{P_1}=\dfrac{T_2}{T_1}\\\Rightarrow P_2=\dfrac{T_2}{T_1}P_1\\\Rightarrow P_2=\dfrac{40+273.15}{30+273.15}\times 200\\\Rightarrow P_2=206.6\ \text{kPa}$

The pressure that would be exerted after the temperature change is $206.6\ \text{kPa}$ .

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2 years ago

Give the correct balanced equation for the single replacement reaction of magnesium with aluminum oxide. A) Mg + AlO → MgO + Al

solniwko [45]

Answer is "C".

Explanation

Single replacement reaction is a type of reaction which one reactant reacts with another and makes a product by replacing one element by another.

Mg (Magnesium) reacts with Al₂O₃ (Aluminium oxide) and produces MgO (Magnesium oxide) and Al (Aluminium) as products. Here Al is replaced by Mg. Reaction is
Mg + Al₂O₃ → MgO + Al

To balance the reaction equation, both left and right hand sides should have same number of atoms in each element.
Here,
Left Hand Side has Right Hand Side has
Mg = 1 atom Mg = 1 atom
Al = 2 atom Al = 1 atom
O = 3 atom O = 1 atom

First step : balance the O atoms in both sides. To do that "3" should be added before MgO.

Second step : After balancing O atoms, there will be 3 Mg atoms in right hand side. Hence to balance Mg atoms again "3" should be added before Mg in left hand side

Third step : as the final step balance the Al atoms by adding "2" before Al in the right hand side.

Then final balanced equation should be
3Mg + Al₂O₃ → 3MgO + 2Al

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2 years ago

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Answer:

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