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pickupchik [31]
3 years ago
13

How much ice at 0°C could be melted by the addition of 15 kJ of heat? (ΔHfus = 6.01 kJ/mol)

Chemistry
2 answers:
BARSIC [14]3 years ago
7 0

Answer:

d. 45 g

Explanation:

The amount of ice melted is:

\Delta n = \frac{15\,kJ}{6.01\,\frac{kJ}{mol} }

\Delta n = 2.496\,moles

\Delta m = \Delta n \cdot M_w

\Delta m = (2.496\,moles)\cdot \left(18\,\frac{g}{mol} \right)

\Delta m = 44.928\,g

anzhelika [568]3 years ago
5 0

Answer: d.45 g

Explanation:see attached photo

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Which term can be used to describe the process in the reaction below? 2 NaHCO3 (s) → Na2CO3 (s) + H2O (g) + CO2 (g)
Setler79 [48]

Answer:

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Explanation:

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4 0
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What would happen to the block if it had a density of 0.500 kg/L and was placed in the same 100.0 L tank of water?
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A 75.0 g sample of dinitrogen monoxide is confined in a 3.q L vessel. What is the pressure( in atm) at 115 celsius
Nonamiya [84]
Data Given:
                  Pressure  =  P  =  ?

                  Volume  =  V  =  3.0 L

                  Temperature  =  T  =  115 °C + 273  =  388 K

                  Mass  =  m  =  75.0 g

                  M.mass  =  M  =  44 g/mol

Solution:
              Let suppose the Gas is acting Ideally. Then According to Ideal Gas Equation,
                                      P V  =  n R T
Solving for P,
                                      P  =  n R T / V      ------ (1)
Calculating Moles,
                                      n  =  m / M

                                      n  =  75.0 g / 44 g.mol⁻¹

                                      n  =  1.704 mol

Putting Values in Eq. 1,

                    P  =  (1.704 mol × 0.08205 atm.L.mol⁻¹.K⁻¹ × 388 K) ÷ 3.0 L

                    P  =  18.08 atm
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