Question

How much ice at 0°C could be melted by the addition of 15 kJ of heat? (ΔHfus = 6.01 kJ/mol)

Answer 1

Answer:

d. 45 g

Explanation:

The amount of ice melted is:

$\Delta n = \frac{15\,kJ}{6.01\,\frac{kJ}{mol} }$

$\Delta n = 2.496\,moles$

$\Delta m = \Delta n \cdot M_w$

$\Delta m = (2.496\,moles)\cdot \left(18\,\frac{g}{mol} \right)$

$\Delta m = 44.928\,g$

Answer 2

Answer: d.45 g

Explanation:see attached photo