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timama [110]
3 years ago
11

The distance from San Francisco to Los Angeles is approximately 385 miles. 1609 m = 1 mile. How many kilometers is this? Do not

enter “kilometers” as part of your answer.
Chemistry
1 answer:
vitfil [10]3 years ago
7 0

Answer:

619.465 kilometers

Explanation:

1609 m = 1 mile

so 385 miles is equal to 619465 meters (385 x 1609= 619465)

1000 meters = 1 km

so 619465 meters is 619.465 kilometers

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What is the base dissociation constant for a weak base at equilibrium, B + H2O <===> BH+ + OH–?
podryga [215]
Depends on what the base is. You would reference the base dissociation chart for that value.
3 0
3 years ago
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When sulfate (SO42-) serves as the electron acceptor at the end of a respiratory electron transport chain, the product is?
o-na [289]

When sulfate (SO₄²⁻) serves as the electron acceptor at the end of a respiratory electron transport chain, the product is hydrogen sulfide (H₂S).

How sulfate acts as electon acceptor and electron donor?

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Learn more about the Electron transport chain with the help of the given link:

brainly.com/question/24372542

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3 0
2 years ago
The major reaction of the unsaturated compounds is:
antiseptic1488 [7]
Its B addition

where an atom adds to the broken double bond of a hydrocarbon and saturates it 

hope that helps
3 0
3 years ago
Read 2 more answers
1 How many moles of solute are in:
Sonbull [250]

Moles of solute for both a and b are the same = 1 mol

<h3>Further explanation</h3>

Given

a 500 cm³ of solution, of concentration 2 mol/dm³

b 2 litres of solution, of concentration 0.5 mol/dm³

Required

moles of solute

Solution

Molarity shows the number of moles of solute in every 1 liter of solution or mmol in each ml of solution

Can be formulated :

\large \boxed {\bold {M ~ = ~ \dfrac {n} {V}}}

a.

V = 500 cm³ = 0.5 L

M = 2 mol/L

n=moles = M x V

n = 2 mol/L x 0.5 L

n = 1 mol

b.  

V = 2 L

M = 0.5 mol/L

n=moles = M x V

n = 0.5 mol/L x 2 L

n = 1 mol

5 0
3 years ago
To gravimetrically analyze the silver content of a piece of jewelry made from an alloy of Ag and Cu, a student dissolves a small
Ipatiy [6.2K]

Answer:

Adding a solution containing an anion that forms an insoluble salt with only one of the metal ions.

Explanation:

The student have in solution Ag⁺ and Cu²⁺ ions but he just want to analyze the silver, that means he need to separate ions.

Centrifuging the solution to isolate the heavier ions <em>FALSE </em>Centrifugation allows the separation of a suspension but Ag⁺ and Cu²⁺ are both soluble in water.

Adding enough base solution to bring the pH up to 7.0 <em>FALSE </em>At pH = 7,0 these ions are soluble in water and its separation will not be possible.

Adding a solution containing an anion that forms an insoluble salt with only one of the metal ions <em>TRUE </em>For example, the addition of Cl⁻ will precipitate the Ag⁺ as AgCl(s) allowing its separation.

Evaporating the solution to recover the dissolved nitrates. <em>FALSE</em> . Thus, you will obtain the nitrates of these ions but will be mixed doing impossible its separation.

I hope it helps!

8 0
3 years ago
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